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NeX [460]
3 years ago
14

Mark and don are planning to sell each of their marble collections at a garage sale. if don has 4 more than 5 times the number o

f marbles mark has, how many does each boy have to sell if the total number of marbles is 70?
Mathematics
1 answer:
natita [175]3 years ago
6 0

Mark and Don have to sell 11 and 59 marbles respectively.

<em><u>Explanation</u></em>

Lets assume, the number of marbles Mark has  is x

As, Don has 4 more than 5 times the number of marbles mark has, so the number of marbles Don has = 5x+ 4

Question says that the total number of marbles is 70. So, the equation will be...

x+(5x+4)= 70\\ \\ 6x+4= 70 \\ \\ 6x = 70-4\\ \\ 6x=66 \\ \\ x= \frac{66}{6}= 11

<em>So, the number of marbles Mark has = 11 </em>

<em>and the number of marbles Don has = (5*11)+4 = 55+4= 59</em>

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Answer:

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Step-by-step explanation:

The Pythagorean theorem tells you the square on the hypotenuse is equal to the sum of the squares on the other two sides. (This is the version you use for problem 2.)

This also means the square on one side is the difference between the square on the hypotenuse and the square on the other side. (Use this version for problems 1 and 3.)

1. ? = 200 in² -75 in² = 125 in²

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