Answer:
(A)
Step-by-step explanation:
From the given figure, we have to prove whether the two given triangles are congruent or similar.
Thus, From the figure, ∠3=∠4 (Vertically opposite angles)
Since, KL and NO are parallel lines and KO and LN are transversals, then
measure angle 1= measure angle 5 that is ∠1=∠5(Alternate angles).
Thus, by AA similarity rule, ΔKLM is similar to ΔONM.
Thus, Option A that is Triangle KLM is similar to triangle ONM because measure of angle 3 equals measure of angle 4 and measure of angle 1 equals measure of angle 5 is correct.
H = 3.
FIRST STEP:
<span>Add 1 to both sides to get rid of the -1 on the left side.
4h-1 = 3h+2
</span><span>4h-1 (+1) = 3h+2 (+1)
</span><span>4h = 3h+3
SECOND (FINAL) STEP:
Subtract 3h from both sides to get rid of the 3h on the right side.
</span>4h(-3h) = 3h+3 (-3h)
h = 3
Hope this helps, sorry if it's hard to understand :)
Answer:
see the explanation
Step-by-step explanation:
we know that
<u><em>Alternate Exterior Angles</em></u> are created where a transversal crosses two lines. Notice that the two alternate exterior angles are equal in measure if the two lines are parallel
In this problem
----> by alternate exterior angles
One way to verify alternate exterior angles is to see that they are the vertical angles of the alternate interior angles
Answer:
x=8a
Step-by-step explanation:
(3/a) x - 4 = 20
add 4 to both sides
(3/a) x = 24
Divide by 3/a
x = 24 / (3/a)
Use KCF (keep change flip)
x = (24/1) x (a/3)
x = 24a / 3
simplify
x = 8a
In the equation f(n) = 2n - 7
f(11) = 15
