Answer:
Explanation:
05/10
Simplifying
1/2
or 2^-1
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The life span of a certain insect in days is uniformly distributed over the interval (20,36). What is the probability the insect
will live 24 days or less? Possible Answers a) .24 b) .25 c) .20 d) .75
1 answer:
Answer:
b) 0.25
Step-by-step explanation:
The required probability is ...
(24 -20)/(36 -20) = 4/16 = 1/4 = 0.25
_____
<em>Comment on the attached graph</em>
The red line is the probability distribution function (pdf) for this uniform distribution. The green line is the cumulative distribution function (cdf) for this uniform distribution. It is the integral of the pdf.
The probability of interest is the value of the cdf at x=24. That value is 0.25, meaning the area under the pdf curve to the left of x=24 is 1/4 of the total area under the pdf curve. That proportion is what is calculated above.
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Answer:
1/3
Step-by-step explanation:
<em>Method 1.</em>
slope = rise/run
Rise is vertical distance.
Run is horizontal distance.
Find two points that are easy to read (on grid intersections):
(2, -1) and (5, 0).
Start at (2, 1). You need to go to (5, 0) by moving only vertically and horizontally. Go up 1 unit. That is a rise of 1. Now go right 3 units. That is a run of 3.
rise = 1
run = 3
slope = rise/run = 1/3
<em>Method 2.</em>
Use the slope formula and two points on the line.
Use points (2, -1) and (5, 0).
slope = 1/3
Answer:
Therefore the variance on the data set is 8.3
Step-by-step explanation:
In order to find the variance of the set of data we first need to calculate the mean of the set, which is given by:
mean = sum of each element / number of elements
mean = (5 + 8 + 2 + 9 + 4)/5 = 5.6
We can now find the variance by applying the following formula:
So applying the data from the problem we have:
s² = [(5 - 5.6)² + (8 - 5.6)² + (2 - 5.6)² + (9 - 5.6)² + (4 - 5.6)²]/(5 - 1)
s² = [(-0.6)² + (2.4)² + (-3.6)² + (3.4)² + (-1.6)²]/4
s² = [0.36 + 5.76 + 12.96 + 11.56 + 2.56]/4 = 8.3
Therefore the variance on the data set is 8.3