Answer:
<em>x = 2.5</em>
Step-by-step explanation:
- 2x - ( - 5 - 4x ) = - 5 ( 2x - 7 )
- 2x + 5 + 4x = - 10x + 35
- 2x + 5 + 4x = - 10x + 35
- 2x + 4x + 10x = 35 - 5
12x = 30
<em>x = </em>
<em> = 2.5</em>
Check the answer:
<em>L.H.S.</em> = - 2(2.5) - [ - 5 - 4(2.5) ] = <em>10</em>
<em>R.H.S.</em> = - 5 [ 2(2.5) - 7 ] = <em>10</em>
Answer:
Step-by-step explanation:
yes, (given number) / 5
Let the only force acting on the ball is the gravity (free-failing) and the ball was initially stationary
vo = 0
s = vot + 1/2 gt^2
s = 1/2 x 10 x (2.2) ^2 = 24.2 m
We are given with a limit and we need to find it's value so let's start !!!!
But , before starting , let's recall an identity which is the <em>main key</em> to answer this question
Consider The limit ;
Now as directly putting the limit will lead to <em>indeterminate form 0/0.</em> So , <em>Rationalizing</em> the <em>numerator</em> i.e multiplying both numerator and denominator by the <em>conjugate of numerator </em>

Using the above algebraic identity ;


Now , here we <em>need</em> to <em>eliminate (√x-2)</em> from the denominator somehow , or the limit will again be <em>indeterminate </em>,so if you think <em>carefully</em> as <em>I thought</em> after <em>seeing the question</em> i.e what if we <em>add 4 and subtract 4</em> in <em>numerator</em> ? So let's try !


Now , using the same above identity ;


Now , take minus sign common in <em>numerator</em> from 2nd term , so that we can <em>take (√x-2) common</em> from both terms

Now , take<em> (√x-2) common</em> in numerator ;

Cancelling the <em>radical</em> that makes our <em>limit again and again</em> <em>indeterminate</em> ;

Now , <em>putting the limit ;</em>
