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mel-nik [20]
3 years ago
7

Determine the formula unit for the compound formed when each pairs of ions interact.

Chemistry
1 answer:
Levart [38]3 years ago
8 0
I think it’s aluminum cyanide but I could be wrong
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What is it asking for?
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3 years ago
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What is the empirical formula of a compound composed of 3.25% hydrogen ( H ), 19.36% carbon ( C ), and 77.39% oxygen ( O ) by ma
Montano1993 [528]

Answer:

The answer to your question is C₂HO₃

Explanation:

Data

Hydrogen = 3.25%

Carbon = 19.36%

Oxygen = 77.39%

Process

1.- Write the percent as grams

Hydrogen = 3.25 g

Carbon = 19.36 g

Oxygen = 77.39 g

2.- Convert the grams to moles

                     1 g of H ----------------- 1 mol

                   3,25 g of H -------------  x

                     x = (3.25 x 1) / 1

                     x = 3.25 moles

                    12 g of C ---------------- 1 mol

                     19.36 g of C ----------  x

                     x = (19.36 x 1) / 12

                     x = 1.61 moles

                     16g of O --------------- 1 mol

                     77.39 g of O ---------  x

                      x = (77.39 x 1)/16

                      x = 4.83

3.- Divide by the lowest number of moles

Carbon = 3.25/1.61 = 2

Hydrogen = 1.61/1.61 = 1

Oxygen = 4.83/1.61 = 3

4.- Write the empirical formula

                        C₂HO₃

4 0
3 years ago
A sample of 211 g of iron (III) bromide is reacted with
Alisiya [41]

FeBr₃ ⇒ limiting reactant

mol NaBr = 1.428

<h3>Further explanation</h3>

Reaction

2FeBr₃ + 3Na₂S → Fe₂S₃ + 6NaBr

Limiting reactant⇒ smaller ratio (mol divide by coefficient reaction)

  • FeBr₃

211 g of Iron (III) bromide(MW=295,56 g/mol), so mol FeBr₃ :

\tt n=\dfrac{mass}{MW}\\\\n=\dfrac{211}{295,56}\\\\n=0.714

  • Na₂S

186 g of Sodium sulfide(MW=78,0452 g/mol), so mol Na₂S :

\tt n=\dfrac{186}{78.0452}=2.38

Coefficient ratio from the equation FeBr₃ :  Na₂S = 2 : 3, so mol ratio :

\tt FeBr_3\div Na_2S=\dfrac{0.714}{2}\div \dfrac{2.38}{3}=0.357\div 0.793

So  FeBr₃ as a limiting reactant(smaller ratio)

mol NaBr based on limiting reactant (FeBr₃) :

\tt \dfrac{6}{3}\times 0.714=1.428

6 0
3 years ago
In the chemical equation: NO(g) + ½Cl2(g) → NOCl(g) How many moles of NOCl(g) are in the balanced chemical equation? fill in bla
Mrrafil [7]

Answer:

1

Explanation:

The numbers in front of the formulas (the coefficients) tell you how many moles of a substance are involved in a reaction.

If no coefficient is shown, we assume it is 1.

NOCl has no coefficient, so 1 mol of NOCl is in the balanced equation.

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You put two open cans of soda on the table. You took one can from the refrigerator and the other from your car. When you open th
jarptica [38.1K]
The soda can from the car will lose CO2 more quickly. This is because of the kinetic energy and behavior of gas molecules under different temperatures. CO2 is more soluble in cold temperatures than hot. Cold temperatures minimize the kinetic energy of gas molecules; thus, preventing the gas from escaping the soda. This is why soda that comes from the refrigerator has more fizz or spirit than soda at room temperature.
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