Answer : The unknown mass of water is, 200.3 grams.
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
As,
= specific heat water
So,
where,
= mass of water = 150 g
= mass of unknown water = ?
= final temperature of mixture = 
= initial temperature of water = 
= initial temperature of unknown water = 
Now put all the given values in the above formula, we get
Therefore, the unknown mass of water is, 200.3 grams.
Answer:
i think it's B CI-35 only
Explanation:
hope this helps
I think it is d because it talks about other things the other ones finest talk about so go with d or c I hope you get it right good luck
A and d is physical, b and c is chemical
Answer : The volume in mL of the sodium carbonate stock solution is 364 mL.
Explanation :
According to dilution law:
where,
= molarity of aqueous sodium carbonate
= molarity of aqueous sodium carbonate stock solution
= volume of aqueous sodium carbonate
= volume of aqueous sodium carbonate stock solution
Given:
= 1.00 M
= 1.58 M
= 575 mL
= ?
Now put all the given values in the above formula, we get:
Therefore, the volume in mL of the sodium carbonate stock solution is 364 mL.
