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brilliants [131]
4 years ago
9

A sample of oxygen gas at a pressure of 1.14 atm and a temperature of 21.5 degrees Celsius, occupies a volume of 815 ml. If the

gas is compressed at constant temperature until it’s pressure is 1.62 atm, the volume of the gas will be what?
Chemistry
1 answer:
maria [59]4 years ago
7 0

Answer:

The volume of the gas will be 573.52 mL.

Explanation:

Boyle’s law states that <u>the  pressure of a fixed amount of gas at a constant temperature is inversely proportional  to the volume of the gas</u>.

The equation for Boyle's law is:

P₁V₁ = P₂V₂

We want to know V₂, that is, the volume of the container after the compression. We rearrange the equation and calculate:

V₂ = P₁V₁ ÷ P₂

V₂ = 1.14 atm × 815 mL ÷ 1.62 atm = 573.52 mL

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Answer:- molar mass of the unknown gas is 71.5 gram per mol.

Solution:- From Graham's law of effusion rates, the rate of effusion of a gas is inversely proportional to the square root of it's molar mass.

When we compare the effusion rates of two gases then the formula for Graham's law is:

\frac{rate_1}{rate_2}=\sqrt{\frac{M_2}{M_1}}

In this formula, V stands for volume and M stands for molar mass

Rate is volume effused per unit time. Since, the volumes are same, the formula could be written as:

\frac{t_2}{t_1}=\sqrt{\frac{M_2}{M_1}}

let's say in formula, subscript 1 is for hydrogen gas and 2 is for the unknown gas.

Molar mass of hydrogen is 2.02 grams per mol and the time taken to effuse it is 2.42 min. The time taken to effuse the unknown gas is 14.4 min and we are asked to calculate it's molar mass. let's plug in the values in the formula:

\frac{14.4}{2.42}=\sqrt{\frac{M_2}{2.02}}

5.95=\sqrt{\frac{M_2}{2.02}}

doing squares to both sides:

35.4=\frac{M_2}{2.02}

M_2=35.4*2.02

M_2=71.5

So, the molar mass of the unknown gas is 71.5 grams per mol.



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