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OlgaM077 [116]
4 years ago
15

Which number would be classified as an integer on the Venn diagram?

Mathematics
1 answer:
victus00 [196]4 years ago
7 0

Integers involve with negative, so D isn't the correct answer the correct answer will be A.

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If the expression 4c + 2b + 4d is subtracted from 3c + 4b + 5d then the answer will be<br>​
kirill [66]

Answer:

1c 2b 1d

Step-by-step explanation:

did the math

6 0
3 years ago
Read 2 more answers
A coffee mixture has beans that sell for $0.20 a pound and beans that sell for $0.68. If 120 pounds of beans create a mixture wo
atroni [7]
Let x be the number of pounds of the $1.35 beans. The cost of those beans is $1.35 * x, or 1.35x. 
<span>Let y be the number of pounds of the $1.05 beans. The cost of those beans is $1.05 * y, or 1.05y. </span>
<span>We know that 120 pounds of the mix sells for $1.15/pound, for a total of 120 * 1.15 = $138. </span>

<span>x + y = 120 </span>
<span>1.35(x) + (1.05)y = 138 </span>

<span>We can rewrite the first as </span>
<span>x = -y + 120 </span>

<span>Now we can substitute (-y + 120) in for (x) in the second equation, because we just proved they're equal. </span>

<span>1.35(x) + 1.05(y) = 138 </span>
<span>1.35(-y + 120) + 1.05y = 138 </span>
<span>-1.35y + 162 + 1.05y = 138 </span>
<span>-0.3y + 162 = 138 </span>
<span>-0.3y = -24 </span>
<span>y = 80 </span>

<span>And since x + y = 120, that means x = 40. </span>

<span>Check: </span>
<span>40 pounds of x at $1.35 costs 40 * 1.35, or $54. </span>
<span>80 pounds of y at $1.05 costs 80 * 1.05, or $84. </span>
<span>Do those add up to our target total, according to the question, of 120 * 1.15 = $138? </span>
3 0
3 years ago
15.7 is it a rational,natural,whole, integer etc?​
taurus [48]

Answer:

Rational because it is a decimal that can be seen as a fraction.

Step-by-step explanation:

8 0
4 years ago
Please help me do it
Lana71 [14]

Step-by-step Explanation:

We are going to solve this problem using integration by parts. We can write the integrand as

\dfrac{4x}{x^2+4x+3} = \dfrac{4x}{(x+3)(x+1)}

\:\:\:\:\:\:\:\:\:\:\:\:\:= \dfrac{A}{x+3} + \dfrac{B}{x+1}

\:\:\:\:\:\:\:\:\:\:\:\:\:= \dfrac{Ax + A + Bx + 3B}{x^2+4x+3}

\:\:\:\:\:\:\:\:\:\:\:\:\:=\dfrac{(A+B)x + (A+3B)}{x^2+4x+3}

Comparing the above term to the left hand side, we can see that

(A + B)x = 4x

A + 3B = 0

Solving for A and B, we find that A = 6 and B = -2 so our integrand becomes

\dfrac{4x}{x^2+4x+3} = \dfrac{6}{x+3} - \dfrac{2}{x+1}

We can now easily integrate this expression as follows:

\displaystyle \int{\dfrac{4x}{x^2+4x+3}}dx = 6\int{\dfrac{dx}{x+3}} - 2\int{\dfrac{dx}{x+1}}

\:\:\:\:\:\:\:\:\:\:\:\:\:= 6\ln|x+3| - 2\ln|x+1| + C

7 0
3 years ago
See image for question.
klio [65]

Answer:

  • See below

Step-by-step explanation:

We get possible sums from 1 + 1 = 2 to 6 + 6 = 12 when we toss two dices together. Total ways 6*6 = 36

a.

<u>Prime numbers:</u>

  • 2, 3, 5, 7, 11 - total 5 outcomes with 15 ways (1+1, 1+2, 1+4, 1+6,2+1, 2+3, 2+5, 3+2, 3+4, 4+1, 4+3, 5+2, 5+6, 6+1, 6+5)
  • P(prime number) = 15/36

b.

<u>Perfect squares:</u>

  • 4, 9 - total 2 outcomes with 3 ways for 4 (1 +3, 2+2, 3+1) and 4 ways for 9 (3+6, 4+5, 5+4,6+3)
  • P(perfect square) = (3 + 4)/36 = 7/36

c.

<u>Perfect cube:</u>

  • 8 - one outcome with 5 ways (2+6,3+5,4+4,5+3,6+2)
  • P(perfect cube) = 5/36
8 0
3 years ago
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