We start with 80 and we add 1 on the first day, 2 on the 2nd, 4 on the 3rd, etc..
Looking at the numbers being added
1 = 20
2 = 21
4 = 22
8 = 23
16 = 24
.
.
.
We start with 80 and we add 2n to it where n represents the number of days into the iteration
with n starting at 0
The function that shows how many stamps we have on any given day is
D
S = 80 + ∑ 2n Where D is the number of days we are into the iteration
n=0
NOTE: This starts at day 0 which would be S = 80 + 20 = 80 + 1 = 81 stamps
Example: To find how many stamps we have on D = 4 we would have
S = 80+20+21+22+23+24
= 80+1+2+4+ 8+16
= 111 stamps
Answer:
Step-by-step explanation:
(5/6) itself is less than 1 (but greater than 0). Thus, anything multiplied by (5/6) will result in a smaller-by-magnitude quantity.
For example, (5/6)(3/4) is LESS than 3/4 because 5/6 is greater than zero but less than 1.
If we want to get B by itself, we need to "undo" every operation being done to it. Those operations are (in order):
- Multiplication by A
- Addition with 3C
To undo these then, we'll need to:
And, since this is an equation, we'll need to do both of those to the right side as well to keep everything equal. Here we go:
AB + 3C - 3C = D - 3C (subtracting 3C)
AB/A = (D - 3C)/A (dividing by A)
B = (D - 3C)/A
And we're done! If you'd like to see it formatted a little nicer, here's this:

Answer:
y - 2 = 3(x + 1)
y - 2 = 3x + 3
y = 3x + 5
Step-by-step explanation: