Answer:
The 90% confidence interval for the mean test score is between 77.29 and 85.71.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 25 - 1 = 24
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.064
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29
The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.
The 90% confidence interval for the mean test score is between 77.29 and 85.71.
Answer:510+510=1020
Step-by-step explanation:
Answer:
The distance of the helicopter from the bristol is approximately 1<u>2.81 miles</u>
Step-by-step explanation:
Given:
Helicopter flies 10 miles east of bristol.
Then the helicopter flies 8 miles North before landing.
To find the direct distance between the helicopter and bristol.
Solution:
In order to find the distance of the helicopter from the bristol before landing, we will trace the path of the helicopter
The helicopter is first heading 10 miles east of bristol and then going 8 miles due north.
On tracing the path of the helicopter we find that the direct distance of the helicopter from the bristol is the hypotenuse of a right triangle formed by enclosing the path of the helicopter.
Applying Pythagorean theorem to find the hypotenuse of the triangle.



Taking square root both sides.

Thus, the distance of the helicopter from the bristol is approximately 12.81 miles
Answer:
Step-by-step explanation:
(5, -30) (6, -36)
(-36 + 30)/(6 - 5) = -6/1 = -6
y + 30 = -6(x - 5)
y + 30 = -6x + 30
y = -6x + 0
y = -6x
Answer:
1. 3 2. 16
Step-by-step explanation:
3x+2/y, x = 3 and y = 6
3(3)/6
Factor the number
3*3*2/3*2
Cancel the common factor (3)
3*2/2
Cancel the common factor (2)
3/1
Simplify
=3
(4a)^3/(b-2), a = 2, b = 4
(4(2)^3/(4-2)
Subtract the numbers:
2^3 * 4/2
Apply exponent rule (a^b*a^c=a^b+c)
= 2^3+1
Add the numbers:
2^4
Simplify:
=16