Question

Which out of the 2 choices is correct ?

Answer 1

Answer:

sinB is correct

Step-by-step explanation:

Calculating each of cos/ sin for ∠B

cosB = $\frac{adjacent}{hypotenuse}$ = $\frac{6}{3\sqrt{5} }$ = $\frac{2}{\sqrt{5} }$ and

$\frac{2}{\sqrt{5} }$ × $\frac{\sqrt{5} }{\sqrt{5} }$ = $\frac{2\sqrt{5} }{5}$ ≠ $\frac{\sqrt{5} }{5}$

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sinB = $\frac{opposite}{hypotenuse}$ = $\frac{3}{3\sqrt{5} }$ = $\frac{1}{\sqrt{5} }$ and

$\frac{1}{\sqrt{5} }$ × $\frac{\sqrt{5} }{\sqrt{5} }$ = $\frac{\sqrt{5} }{5}$

Answer 2

Answer:sinB is correct

Step-by-step explanation

Step-by-step explanation:

Calculating each of cos/ sin for ∠B

cosB =  =  =  and

×  =  ≠

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sinB =  =  =  and

×  =

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