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Effectus [21]
3 years ago
5

Which out of the 2 choices is correct ?

Mathematics
2 answers:
tiny-mole [99]3 years ago
7 0

Answer:

sinB is correct

Step-by-step explanation:

Calculating each of cos/ sin for ∠B

cosB = \frac{adjacent}{hypotenuse} = \frac{6}{3\sqrt{5} } = \frac{2}{\sqrt{5} } and

\frac{2}{\sqrt{5} } × \frac{\sqrt{5} }{\sqrt{5} } = \frac{2\sqrt{5} }{5} ≠ \frac{\sqrt{5} }{5}

--------------------------------------------------------------------------------

sinB = \frac{opposite}{hypotenuse} = \frac{3}{3\sqrt{5} } = \frac{1}{\sqrt{5} } and

\frac{1}{\sqrt{5} } × \frac{\sqrt{5} }{\sqrt{5} } = \frac{\sqrt{5} }{5}

12345 [234]3 years ago
5 0

Answer:sinB is correct

Step-by-step explanation

Step-by-step explanation:

Calculating each of cos/ sin for ∠B

cosB =  =  =  and

×  =  ≠

--------------------------------------------------------------------------------

sinB =  =  =  and

×  =

Read more on Brainly.com - brainly.com/question/12994350#readmore

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