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4 years ago

Which out of the 2 choices is correct ?

Mathematics

2 answers:

tiny-mole [99]4 years ago

7 0

Answer:

sinB is correct

Step-by-step explanation:

Calculating each of cos/ sin for ∠B

cosB = $\frac{adjacent}{hypotenuse}$ = $\frac{6}{3\sqrt{5} }$ = $\frac{2}{\sqrt{5} }$ and

$\frac{2}{\sqrt{5} }$ × $\frac{\sqrt{5} }{\sqrt{5} }$ = $\frac{2\sqrt{5} }{5}$ ≠ $\frac{\sqrt{5} }{5}$

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sinB = $\frac{opposite}{hypotenuse}$ = $\frac{3}{3\sqrt{5} }$ = $\frac{1}{\sqrt{5} }$ and

$\frac{1}{\sqrt{5} }$ × $\frac{\sqrt{5} }{\sqrt{5} }$ = $\frac{\sqrt{5} }{5}$

12345 [234]4 years ago

5 0

Answer:sinB is correct

Step-by-step explanation

Step-by-step explanation:

Calculating each of cos/ sin for ∠B

cosB = = = and

× = ≠

--------------------------------------------------------------------------------

sinB = = = and

× =

Read more on Brainly.com - brainly.com/question/12994350#readmore

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Answer:

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Step-by-step explanation:

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cupoosta [38]

Answer:

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Step-by-step explanation:

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3 years ago

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ludmilkaskok [199]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

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Zinaida [17]

Answer:

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Step-by-step explanation:

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