We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:
.
.
does not exist as 
.
<h3>How to determinate the limit in a piecewise function</h3>
In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.
According to the definition of <em>lateral</em> limit and by observing carefully the figure, we have the following conclusions:
- .
- .
- does not exist as .
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The answer is x=3 i believe
So if you're adding two negatives you move left, positive you move right, and when you have to determine a negative, and a positive you just have to see which one is the farthest from zero which the farthest one's sign is either positive, or negative. Positive to move right, and negative to move left.
Let
R = Ralph's age
S = Sara's age
First statement is translated as:
S = 3R
Second statement is translated as:
S + 4 = 2(R + 4)
Use the first equation to be substituted into the second one in terms of R which is the one we are actually going to solve for Ralph's age.
Since S = 3R, then
3R + 4 = 2(R + 4)
3R + 4 = 2R + 8
3R - 2R = 8 - 4
R = 4 years old
