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Liono4ka [1.6K]
3 years ago
8

what is the square root of 98 what is the square root of y to the 6th what is the square root of a to the 7th what is the square

root of 12x^3y^2 what is the square root of 36x^2y^4 what is the square root of 48ab^3 what is the square root of 10a^5b^2 what is the square root of 20x^3y^10
Mathematics
1 answer:
Bogdan [553]3 years ago
7 0
1. sqrt(98) = 7 sqrt(2)
2. sqrt(y^6) = y^3
3. sqrt(a^7) = a^7/2
4. sqrt(12x^3y^2) =  2xy sqrt(3x)
5. sqrt(36x^2y^4) = 6xy^2
6. sqrt(48ab^3) = 4b sqrt(3ab)
7. sqrt(10a^5b^2) =  a^2b sqrt(10a)
8. sqrt(20x^3y^10 =  2xy^5 sqrt(5x)
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Help solve these please 1.w + 10 = 25
4vir4ik [10]

Answer:

1. w = 15

2. b = 4.8

3. s = 9.7

4. p =15

5. m = -3.2

Step-by-step explanation:

1.w + 10 = 25

we have to find the value of w, so moving 10 from left side to right side

w= 25 - 10

w = 15

2. 7.2 + b = 12

we have to find the value of w, so moving 7.2 from left side to right side

b= 12 - 7.2

b= 4.8

3. 5.3 + s = 15

s= 15 - 5.3

s= 9.7

4.p + (-25) = -10

p-25 = -10

p= -10 + 25

p= 15

3. m + (-1.6) = -4.8

m - 1.6 = -4.8

m = -4.8 + 1.6

m= -3.2

3 0
3 years ago
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The temperature is 1°C below zero.
Alenkasestr [34]

Answer:

-1 is the answer :)

5 0
2 years ago
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Can someone help me understand how to get 24 7/100 to a decimal form
ivolga24 [154]

7/100=0.07

24+0.07=24.07

3 0
3 years ago
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What is the equation of the line that passes through the pont (6,2) and has a<br> of -2/3
ss7ja [257]

Answer:  y

=

−

2

3

x

+

2

Explanation:

Given that we have the slope and a point on the graph we can use the point slope formula to find the equation of the line.

Point-Slope Formula:  

y

−

y

1

=

m

(

x

−

x

1

)

, where  

m

is the slope of the line and  

x

1

and  

y

1

are x and y coordinates of a given point.

We can summarize the information already given:

m

=

−

2

3

x

1

=

6

y

1

=

−

2

Using this information, we can substitute these values onto the point-slope formula:

y

−

(

−

2

)

=

−

2

3

(

x

−

(

6

)

)

y

+

2

=

−

2

3

(

x

−

6

)

The equation above is the equation of the line in point-slope form. If we wanted to have the equation in  

y

=

m

x

+

b

form then we simply solve the equation above for  

y

y

+

2

=

−

2

3

x

+

12

3

y

+

2

−

2

=

−

2

3

x

+

12

3

−

2

y

=

−

2

3

x

+

12

3

−

2

(

3

3

)

y

=

−

2

3

x

+

12

3

−

6

3

y

=

−

2

3

x

+

6

3

y

=

−

2

3

x

+

2y

=

−

2

3

x

+

2

Explanation:

Given that we have the slope and a point on the graph we can use the point slope formula to find the equation of the line.

Point-Slope Formula:  

y

−

y

1

=

m

(

x

−

x

1

)

, where  

m

is the slope of the line and  

x

1

and  

y

1

are x and y coordinates of a given point.

We can summarize the information already given:

m

=

−

2

3

x

1

=

6

y

1

=

−

2

Using this information, we can substitute these values onto the point-slope formula:

y

−

(

−

2

)

=

−

2

3

(

x

−

(

6

)

)

y

+

2

=

−

2

3

(

x

−

6

)

The equation above is the equation of the line in point-slope form. If we wanted to have the equation in  

y

=

m

x

+

b

form then we simply solve the equation above for  

y

y

+

2

=

−

2

3

x

+

12

3

y

+

2

−

2

=

−

2

3

x

+

12

3

−

2

y

=

−

2

3

x

+

12

3

−

2

(

3

3

)

y

=

−

2

3

x

+

12

3

−

6

3

y

=

−

2

3

x

+

6

3

y

=

−

2

3

x

+

2

Step-by-step explanation:

8 0
3 years ago
#2: Solve the linear system below using the elimination method. Type your
MariettaO [177]

The given linear system is:

\displaystyle \left \{ {{5x+7y=33} \atop {11x+7y=39}} \right.

The question is asking to solve using elimination. When eliminating, you can either eliminate x or y. In this system, y is much easier to eliminate. The y variable in both equations are 7y. To eliminate, one of them has to be negative, so multiply one of the equations by -1.

I will be multiplying the second equation by -1.

\displaystyle (11x + 7y = 39) \times -1 = -11x-7y=-39

Rewrite the system:

\displaystyle \left \{ {{5x+7y=33} \atop {-11x-7y=-39}} \right.

Subtract:

5x+7y=33\\-11x-7y=-39

5x-11x=33-39\\-6x=-6

Lastly, you need to leave the variable x alone. The variable is currently -6x or -6 times x. To remove it, you need to do the opposite of it, which is dividing by -6.

\displaystyle \frac{-6x}{-6} =\frac{-6}{-6}

\displaystyle x=1

Now that you have the value of x, substitute it into one of the equations to find y. I will be substituting it into the first equation.

5x+7y=33 \rightarrow 5(1)+7y=33

Open the parentheses and multiply:

5+7y=33

Move 5 to the other side to leave the variable alone:

5+7y-5=33-5

You will be subtracting since you're "removing" it by doing the opposite of it.

7y=28

Lastly, divide both sides by 7 to leave y alone.

\displaystyle \frac{7y}{7} =\frac{28}{7}

y=4

\displaystyle (x,y) \rightarrow (1, 4)

The answer is (1, 4).

8 0
2 years ago
Read 2 more answers
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