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3 years ago

Una ciudad tenía 8000 habitantes a final del año 2000. Cada año su población se incrementa en un 0.5 %

Mathematics

1 answer:

Digiron [165]3 years ago

4 0

Answer:

The correct answer is 2030.

Step-by-step explanation:

To start we must analyze the information we have.

We know that a city has 8000 inhabitants and that each year this number increases by 0.5%. That means that each year it has 40 more inhabitants:

(8000 . 0,5) : 100 = 40

Having this information we could do a cross multiplication:

1 year ------- 40 inhabitants

x years ------- 81200

81200 = 40.x

x = 81200 : 40

x = 2030

In this way we can verify that the correct answer is 2030.

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Answer:

For a: The probability of getting a red or blue ball is 0.48

For b: The probability of getting a white, blue or orange ball is 0.81

For c: The probability of getting neither white or orange ball is 0.48

Step-by-step explanation:

Probability is defined as the extent to which an event is likely to occurs. It is measured by the ratio of the favorable outcomes to the total number of possible outcomes.

$\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of favorable outcomes}}$ .......(1)

We are given:

Number of red balls in a box = 12

Number of white balls in a box = 18

Number of blue balls in a box = 19

Number of orange balls in a box = 15

Total balls in a box = [12 + 18 + 19 + 15] = 64

For a:

Number of favorable outcomes (ball must be red or blue) = [12 + 19] = 31

Total number of outcomes = 64

Putting values in equation 1, we get:

$\text{Probability of getting a red or blue ball}=\frac{31}{64}=0.48$

For b:

Number of favorable outcomes (ball must be white or blue or orange) = [18 + 19 + 15] = 52

Total number of outcomes = 64

Putting values in equation 1, we get:

$\text{Probability of getting a white or blue or orange ball}=\frac{52}{64}=0.81$

For c:

Number of favorable outcomes (ball must be white or orange) = [18 + 15] = 33

Total number of outcomes = 64

Putting values in equation 1, we get:

$\text{Probability of getting a white or orange ball}=\frac{33}{64}=0.52$

Probability of getting a ball which is neither white or orange = [1 - (Probability of getting a white or orange ball)] = [1 - 0.52] = 0.48

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