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GuDViN [60]
3 years ago
6

Which fraction is equivalent to 4%

Mathematics
2 answers:
navik [9.2K]3 years ago
7 0
The answer will be C. 1/25
Harman [31]3 years ago
6 0
1/25 it equals 4 yasss
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Post Test: Introduction to Geometry and Transformations
Gala2k [10]

Answer:

whats the question though?

Step-by-step explanation:

3 0
2 years ago
A recipe requires 3 cup of cornstarch. You can only measure using 1/4 cup. How many 1/4 cups are needed in the recipe
anastassius [24]

Answer:

12

Step-by-step explanation:

to make 1 cup with 1/4 cup you need to put 4.

therefore;

number of 1/4 cups needed = 3x4=12

7 0
2 years ago
What is the correct answer?
Tasya [4]

Given:

The function is

f(x)=(x+3)^2(x-5)^6

To find:

The zeros of the given function.

Solution:

The general form of polynomial is

P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}       ...(i)

where, a is a constant, c_1,c_2,...,c_n are zeros of respective multiplicities m_1,m_2,...,m_n.

We have,

f(x)=(x+3)^2(x-5)^6

On comparing this with (i), we get

c_1=-3,m_1=2

c_2=5,m_2=6

It means, -3 is a zero with multiplicity 2 and 5 is a zero with multiplicity 6.

Therefore, the correct option is B.

5 0
2 years ago
Write a reclusive rule for the sequence, then give the next two numbers in the sequence 6,1,7,8,15,23
vlabodo [156]

Answer:

aₙ = aₙ₋₁ + aₙ₋₂

where:

a₁ = 6

a₂= 1.

Step-by-step explanation:

We have the sequence:

6, 1, 7, 8, 15, 23, ...

Is easy to see that this sequence works as follows:

You take 2 consecutive numbers, and the next number is the sum of these two.

Then we have:

6 + 1 = 7

1 + 7 = 8

7 + 8 = 15

8 + 15 = 23

Then the n-th term is equal to the sum of the (n - 1) term and the (n - 2) term.

This is written as:

aₙ = aₙ₋₁ + aₙ₋₂

Because in the recursive rule needs two previous terms, we need to specify  the two first terms of the sequence.

Then we need to write also:

a₁ = 6

a₂= 1.

5 0
3 years ago
Please help quick will give brainly points
k0ka [10]

Answer: They are not inverse.

Step-by-step explanation:

6 0
2 years ago
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