1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
frez [133]
3 years ago
7

A pilot can travel 450 miles with the wind in the same amount of time as 360 miles against the wind. Find the speed of the wind

if the​ pilot's speed in still air is 315 miles per hour.
Mathematics
1 answer:
Lunna [17]3 years ago
4 0

Given:

A pilot can travel 450 miles with the wind in the same amount of time as 360 miles against the wind.

Pilot's speed in still air is 315 miles per hour.

To find:

The speed of the wind.

Solution:

Let the speed of wind be x miles per hour.

Speed with wind = 315+x miles per hour

Speed against wind = 315-x miles per hour

We know that,

Time=\dfrac{Distance}{Speed}

According to the question,

\dfrac{450}{315+x}=\dfrac{360}{315-x}

Divide both sides by 90.

\dfrac{5}{315+x}=\dfrac{4}{315-x}

By cross multiplication, we get

5(315-x)=4(315+x)

5(315)-5x=4(315)+4x

5(315)-4(315)=4x+5x

(5-4)315=9x

Divide both sides by 9.

\dfrac{(1)315}{9}=x

35=x

Therefore, the speed of wind is 35 miles per hour.

You might be interested in
Seven times the difference of x and 2 is 28​
liq [111]

Answer:

7(x-2)=28

7x-14=28

7x=28-14

x=14÷7

Therefore x= 2

8 0
3 years ago
Which number has a repeating decimal form?
Genrish500 [490]
2/6 has a repeating decimal form.

If you plug it in the calculator, you get 0.3333... with the 3 repeating.

Hope this helps.

If you have any questions, place it in the comment section below.
5 0
4 years ago
What would the following equation look like in augmented matrix form? 2x+y=6 x-3y=-2
xz_007 [3.2K]
<span><span><span><span>2x</span>+y</span>+<span>−y</span></span>=<span>6+<span>−y</span></span></span><span><span>2x</span>=<span><span>−y</span>+6</span></span>Step 2: Divide both sides by 2.<span><span><span>2x</span>2</span>=<span><span><span>−y</span>+6</span>2</span></span><span>x=<span><span><span><span>−1</span>2</span>y</span>+3</span></span>Answer:<span> x=<span><span><span><span>−1</span>2</span>y</span>+3</span></span>


x-3=-2
x-3+3=-2+3
answer x=1

4 0
3 years ago
Please help !! Will grant brainliest ..
Free_Kalibri [48]

(3,3)

(9,4)

(3,5)

(4,4)

5 0
4 years ago
Which graph shows the asymptotes of the function f(x)=4x-8/2x+3
Ksju [112]

Answer:

Graph C

Step-by-step explanation:

Assuming you mean \displaystyle f(x)=\frac{4x-8}{2x+3}:

  • Our vertical asymptote will be the line equal to the solution of 2x+3=0, which is x=-\frac{3}{2}
  • Our horizontal asymptote will be equal to the ratio of the leading coefficients since they have the same degree, so y=2

Thus, the correct graph is C.

8 0
3 years ago
Other questions:
  • Trials in an experiment with a polygraph include 97 results that include 23 cases of wrong results and 74 cases of correct resul
    5·1 answer
  • Elizabeth had 12 stamps. She decided to write letters to some of her relatives. After she sent herietters, she had 6 stamps left
    6·1 answer
  • The sum of two polynomials is why Z squared minus 3Z squared minus 4Y +4 if one of the palm will normally else is Y -4
    9·1 answer
  • Suppose x = 7 is a solution to the equation 4x − 2(x + a) = 8. Find the value of a that makes the equation true. A: 2 B: 3 C: -2
    7·1 answer
  • What is the sum of 6/13 and 1/8.why is the sum greater then 1/2
    15·1 answer
  • Which set of points lies on given graph?
    7·1 answer
  • And this one please.
    14·1 answer
  • 4. A varies directly as r. If A = 12, when r = 2, calculate:<br>a) the value of A, when r=5<br>​
    10·2 answers
  • Mr cadwell wants to purchase a motorcycle. he has financing options a and b to chose from, as shown below.
    7·1 answer
  • If (1, 0) is an ordered pair of the function F(x), which of the following is an
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!