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alisha [4.7K]
3 years ago
11

What could J. J. Thomson conclude from his experiments? Atoms are mostly empty space. Most of the mass of the atom is concentrat

ed in the center. Atoms must balance positive and negative particles. Atoms are indivisible.
Chemistry
2 answers:
RideAnS [48]3 years ago
4 0

Answer:

c on edge

Explanation: just took the test

Oduvanchick [21]3 years ago
3 0

Answer:

atoms must balance positive and negative particles

Explanation:

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Given that 10.00mL of 0.1894M CH3COOH was titrated with 0.2006M NaOH in this experiment, calculate the volume, in mL, of NaOH re
sertanlavr [38]

Answer:

V_{base}=9.442mL

Explanation:

Hello!

In this case, when acetic acid is titrated with sodium hydroxide, the following chemical reaction is carried out:

CH_3COOH+NaOH\rightarrow CH_3COONa+H_2O

Whereas there is a 1:1 mole ratio between the acid and the base, which means that at the equivalence point we evidence:

n_{acid}=n_{base}

Which in terms of volumes and concentrations is written as:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, solving for the required volume of base, we obtain:

V_{base}=\frac{M_{acid}V_{acid}}{M_{base}}=\frac{0.1894M*10.00mL}{0.2006M}\\\\ V_{base}=9.442mL

Best regards!

7 0
3 years ago
What will be the final speed of an electron released from rest at the negative plate?
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Potential energy U= k*Q*q/r
doubling the charge Q doubles the potential energy. Since this will just be converted into kinetic energy u will double tht
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3 years ago
The tendency of a moving object to continue moving in a straight line or a stationary object to remain in place is called
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The tendency of a moving object to continue moving in a straight line or a stationary object to remain in place is called inertia.

Answer: C) or the third option.
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3 years ago
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What is the mass of 2.70 ×10^22 molecules of NaOH (Molar mass = 40.0 g/mol)?
Viefleur [7K]
Data:
Molar Mass of NaOH = 40 g/mol

Solving: <span>According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules
</span>
1 mol -------------------- 6.02*10²³ molecules
y mol -------------------- 2.70*10²² molecules

6.02*10²³y = 0.270*10²³ 
y =  \frac{0.270*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}{6.02*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}
\boxed{y \approx 0.04\:mol}


Solving: <span>Find the mass value now
</span>
40 g ----------------- 1 mol of NaOH
x g ------------- 0.04 mol of NaOH

x = 40*0.04
\boxed{\boxed{x = 1.6\:g}}\end{array}}\qquad\quad\checkmark

Answer:
The mass is 1.6 grams
6 0
3 years ago
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