What could J. J. Thomson conclude from his experiments? Atoms are mostly empty space. Most of the mass of the atom is concentrat
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The question is incomplete, complete question is :
Consider the decomposition of red mercury(II) oxide under standard state conditions.
Given :
Enthalpy change of the reaction = ΔH = -90.83 kJ/mol
(a) Is the decomposition spontaneous under standard state conditions?
(b) Above what temperature does the reaction become spontaneous?
Answer:
a) The decomposition is spontaneous under standard state conditions.
b)The reaction will spontaneous above -419.69 Kelvins.
Explanation:
Given :
Entropy change of the reaction ; ΔS
Enthalpy change of the reaction = ΔH = -90.83 kJ/mol = -90830 J/mol K
1 kJ = 1000 J
At standard condition the value of temperature = T = 298 K
ΔG = ΔH - TΔS
ΔG = -90830 J/mol K - 298 K × 216.42 J/mol K = -155,323.16 J/mol
ΔG < 0 ( spontaneous)
The decomposition is spontaneous under standard state conditions.
b) Above what temperature does the reaction become spontaneous
Let the ΔG = 0
Enthalpy change of the reaction = ΔH = -90.83 kJ/mol = -90830 J/mol K
ΔG = ΔH - TΔS
0 = -90830 J/mol K - T × 216.42 J/mol K
T = -419.69 K
The reaction will spontaneous above -419.69 Kelvins.
Answer : The type of compound created is Ionic compound and the chemical formula is KCl.
Explanation :
- Potassium has 1 electron in its valence shell and chlorine has 7 electrons in its valence shell.
- The potassium loses 1 valence electron & make a positive charged ion and chlorine picks it up & make a negative charged ion and then they attract to each other.
- Potassium and chlorine atom combine to form potassium chloride by the ionic bonding.
- An ionic compound is made of a metal and non-metal element. And in this case, potassium is a metal element and chlorine is a non-metal element.
The ionic compound formation is,
The Chemical formula is KCl.