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2 years ago

The product of the reaction between the following substances was treated with h2o. Draw the final product.

Chemistry

1 answer:

Viefleur [7K]2 years ago

5 0

Answer:

See explanation and picture

Explanation:

Question is incomplete, however, I found this question on several sites and most of them, have the same substances, so I'm gonna do it with that example to give you a hint of how to do it with yours, in case, it's a different substance.

First, we have a ketone and another substance, with MgCl. This is tipically the Grignard reagent, and this is often used to produce a tertiary alcohol.

The mechanism and final product is the following (See attached picture).

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What is the ph of a 3x10-8M H+ solution

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Answer:

The pH of the solution is 7, 52

Explanation:

The pH gives us an idea of the acidity or alkalinity of a solution. Is calculated:

pH = -log (H +)

pH= -log ( 3x10-8)= 7, 52

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Answer:

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Explanation:

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Read 2 more answers

Write a net ionic equation for the overall reaction that occurs when aqueous solutions of nitrous acid and sodium hydroxide are

Bess [88]

Answer:

H+(aq) + OH-(aq) → H2O(l)

Explanation:

Step 1: Data given

nitrious acid = HNO3

sodium hydroxide = NaOH

Step 2: The unbalance equation

HNO3(aq) + NaOH(aq) →NaNO3(aq) + H2O(l)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side (Ba^2+ and Br-), look like this:

H+(aq) + NO3-(aq) + Na+(aq) + OH-(aq) →Na+(aq) +NO3(aq) + H2O(l)

H+(aq) + OH-(aq) → H2O(l)

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3 years ago