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I am Lyosha [343]
2 years ago
14

Pollutants may be natural or man-made true or false​

Chemistry
2 answers:
enyata [817]2 years ago
4 0

Answer:

It's <em>True</em> very true darling

USPshnik [31]2 years ago
4 0
True
Explanation:
It is very true that pollutants can be created both naturally and man-made this is because that all animals produce or intensionally cause pollution, and not only animals there are many non natural causes for pollution too some examples of this is volcanic dust, sea salt particles, photochemically formed ozone, and products of forest fibres, an example of pollution that animals make is the methane and co2 produced after the digestion of foods in animals such as cows.Alyought humans are the leading cause of pollution with the increasing usage of plastic and the gas emmited from factories it is true that pollution can be caused by animals and by other non living causes.
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Which chemical equation demonstrates the law of conservation of mass!
zlopas [31]

Answer:

F. 2NO + 02 —> 2NO

H. 4NH3 + 502 —> 4NO + 6H20

Explanation:

The law of conservation of mass states that matter can neither be created nor destroyed during a chemical reaction but can be convert from one form to another.

2NO + 02 —> 2NO

From the above, the total number of N on the left balance the total number on the right i.e 2 atoms of N on both side of the equation.

The total number of O on the left balance the total number on the right i.e 2 atoms of O on both side of the equation. This is certified by the law of conservation of mass.

4NH3 + 502 —> 4NO + 6H20

From the above, the total number of N on the left balance the total number on the right i.e 4 atoms of N on both side of the equation.

The total number of O on the left balance the total number on the right i.e 10 atoms of O on both side of the equation.

The total number of H on the left balance the total number on the right i.e 12 atoms of O on both side of the equation.

This is certified by the law of conservation of mass.

The rest equation did not conform to the law of conservation of mass as the atoms on the left side did not balance those on the right side

5 0
3 years ago
If the chemist mistakenly makes 250 mL of solution instead of the 200 mL, what molar concentration of sodium nitrate will the ch
Evgesh-ka [11]

Answer:

0.120M is the concentration of the solution

Explanation:

<em>Assuming the mass of sodium nitrate dissolved was 2.552g</em>

<em />

Molar concentration is an unit of concentration widely used in chemsitry defined as the moles of solute (In this case NaNO3) in 1L of solution.

To find this question we must find the moles of NaNO3 in 2.552g. With this mass and the volume (250mL = 0.250L) we can find molar concentration as follows:

<em>Moles NaNO3 -Molar mass: 84.99g/mol-</em>

2.552g * (1mol / 84.99g) = 0.0300 moles NaNO3

<em>Molar concentration:</em>

0.0300 moles NaNO3 / 0.250L =

<h3>0.120M is the concentration of the solution</h3>
7 0
3 years ago
Which term names the action that is happening when an acid eats away part of a metal bar
dangina [55]

Answer:

corrosion

Explanation:

8 0
3 years ago
If you have 5 moles of carbon dioxide at 30degrees C and under 600mmHg of pressure, what will the volume be
trapecia [35]

Answer:

157.64 L

Explanation:

We'll begin by converting 30 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 30 °C

T(K) = 30 °C + 273

T (K) = 303 K

Next, we shall convert 600 mmHg to atm. This can be obtained as follow:

760 mmHg = 1 atm

Therefore,

600 mmHg = 600 mmHg × 1 atm / 760 mmHg

600 mmHg = 0.789 atm

Finally, we shall determine the volume of the gas. This can be obtained as follow:

Number of mole (n) = 5 moles

Temperature (T) = 303 K

Pressure (P) = 0.789 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

PV = nRT

0.789 × V = 5 × 0.0821 × 303

0.789 × V = 124.3815

Divide both side by 0.789

V = 124.3815 / 0.789

V = 157.64 L

Therefore, the volume of the gas is 157.64 L

7 0
3 years ago
WILLL GIVE BRAINLIEST IF YOU ANSWERRR PLEASEEEE IM LITERALLY BEGGING YOU I PUT THIS QUESTION IN SOO MANY TIMES I HAVEN'T GOTTEN
tino4ka555 [31]

Answer:

The answer is 375.54 g of AgBr

Explanation:

Mass (g) = Concentration (mol/L) x volume (L) x Molecular Weight of AgBr (g/mol)

Mass = 2M x 1L x 187.77 g/mol

Mass = 375.54g

6 0
2 years ago
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