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Tanzania [10]
3 years ago
7

Convert R=(12)/4+8sin the theta to rectangular form

Mathematics
1 answer:
kompoz [17]3 years ago
5 0
r=\dfrac{12}{4+8\sin\theta}=\dfrac3{1+2\sin\theta}

Let y=2\sin\theta, and recall that in polar coordinates, r=\sqrt{x^2+y^2}. This means you have

\sqrt{x^2+y^2}=\dfrac3{1+y}

You can stop there, or try to find something that looks somewhat nicer.

x^2+y^2=\dfrac9{(1+y)^2}
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