Answer:
A. v(t) = sin (2πft + π/2) = A cos (2πft)
Step-by-step explanation:
According to trigonometry friction, the following relationship are true;
Sin(A+B) = sinAcosB + cosAsinB
We will be using this relationship to check which option is true.
Wave equation is represented as shown;
y(t) = Asin(2πft±theta)
For positive displacement,
y(t) = Asin(2πft+theta)
If theta = π/2
y(t) = Asin(2πft+π/2)
y(t) = A[ sin 2πftcosπ/2 + cos2πft sin π/2]
Since sinπ/2 = 1 and cos (π/2) = 0
y(t) = A[ sin 2πft (0)+ cos2πft (1)]
y(t) = A[0+ cos2πft]
y(t) = Acos2πft
Hence the expression that is true is expressed as;
v(t) = Asin(2πft+π/2) = Acos2πft
The tangent line to a circle makes an angle of 90 degrees with the radius.
If |FG| is tangent to circle E. then
30^2 = 26^2 + 17^2
which is not true.
Therefore, line segment FG is not tangent to circle E.
Answer: y=2x-5. so it's 2
remember the following equation: y=mx+b.
the slope is always m, the y intercept is b.
Answer:
10 ÷ 16
Step-by-step explanation:
The computation is shown below
Given that
Paul required to buy 5 by 8 pound of peanuts
And, the scale at the store is in sixteenths
So, the measure that should be equivalent is
Here the denominator should be 16 so it should be multiplied by 2
= 5 ÷ 8 × 2 ÷ 2
= 10 ÷ 16
Answer:
16
Step-by-step explanation:
