Which of these numbers 3 4 5 6 7 8 makes the inequity true?20>4b

Mathematics

1 answer:

USPshnik [31]3 years ago

4 0

Answer:

3 and 4

Step-by-step explanation:

Solving the inequality

20 > 4b ( divide both sides by 4 )

5 > b, thus

b < 5

3 and 4 are the only values that make the inequality true

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Expreessions represent The sum of 3 and n

weeeeeb [17]

Answer:

3+n

Step-by-step explanation:

Simple questions but it can be technical atimes, according to the question we are to solve in terms of n, simple...

The sum of 3 and n can be written as 3+n

This cannot be solved further because there are two different variables and it is impossible to add them together

Therefore the final answer is 3+n

But in case a value is given for n we can then substitute and solve further

Hope this will help you

6 0

3 years ago

Read 2 more answers

If <img src="https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-2" id="TexFormula1" title="f(x)=x^2-2" alt="f(x)=x^2-2" align="absmiddle"

jek_recluse [69]

Answer:

$\boxed{f(6) = 34}$

Step-by-step explanation:

Composition of functions occurs when we have two functions normally written similar or exactly like f(x) & g(x) - you can have any coefficients to the (x), but the most commonly seen are f(x) and g(x). They are written as either f(g(x)) or (f o g)(x). Because our composition is written as $(f \circ g)(2)$ , we are replacing the x values in the g(x) function with 2 and simplifying the expression.

$g(2) = 3(2)$

$g(2) = 6$

Now, because we are composing the functions, this value we have solved for now replaces the x-values in the f(x) function. So, f(x) becomes f(6), and we use the same manner as above to simplify.

$f(6) = (6)^2-2$