All categories

4 years ago

What is a magnetosphere?

1 answer:

4 0

A magnetosphere is the region of space surrounding an astronomical object in which charged particles are controlled by that object's magnetic field. The magnetic field near the surface of many astronomical objects resembles that of a dipole.

You might be interested in

If you push a book against a wall hard enough, it will not slide down even though gravity is pulling it. Use what you know about

Rashid [163]

The frictional force is too much compared to the gravitational force

Explanation:

This is because of the great amount of frictional force between the book and the wall.

Also, the force of gravity on the book is not high enough to cause motion of the book to slide downs.

Frictional force is a force that opposes motion.

For the book to slide down, it must overcome the force of friction acting on it opposite to the direction of gravity.
According to newton's first law 'a body will remain in its state of rest or uniform motion unless acted upon by an external force'.
Assuming the external force is gravitational force, clearly we see that the force is less than the frictional exerted on the book by pinning it to the wall.
This frictional force is a static friction that is on a body at rest, it must be overcome by a larger force before motion takes place.

Fr > fg

Fr is the frictional force

fg is the gravitational force

learn more:

Newton laws brainly.com/question/11411375

#learnwithBrainly

3 0

4 years ago

How does the state of matter of the medium through which the sound waves and light waves travel theough affect their velocity

yanalaym [24]

Answer:

idk

Explanation:

idk

5 0

3 years ago

2. A Plate 0.02 mm distance from a fixed Plate moves at a velocity Of 0.6mls and requires a force of 1.962 N Per unit area to ma

Marizza181 [45]

Answer:

6.54 × 10⁻⁵ Pa-s

Explanation:

Since the shear force, F = μAu/y where μ = viscosity of fluid between plates, A = area of plates, u = velocity of fluid = 0.6 m/s and y = separation of plates = 0.02 mm = 2 × 10⁻⁵ m

Since F = μAu/y

F/A = μu/y where F/A = force per unit area

Since we are given force per unit area, F/A = 1.962 N per unit area = 1.962 N/m²

So, μ = F/A ÷ u/y

substituting the values of the variables into the equation, we have

μ = F/A ÷ u/y

μ = 1.962 N/m² ÷ 0.6 m/s/2 × 10⁻⁵ m

μ = 1.962 N/m² ÷ 0.3 × 10⁵ /s

μ = 6.54 × 10⁻⁵ Ns/m²

μ = 6.54 × 10⁻⁵ Pa-s

5 0

3 years ago

10. The Force between two objects is 2 Newtons. One object has a mass of 6.2kg.

insens350 [35]

Answer:

$m_2=9.79\times 10^{12}\ kg$

Explanation:

Given that.

The force between two objects, F = 2 N

Mass of object 1, m₁ = 6.2 kg

Distance between the center of one object to the center of the other object, r = 45 m

We need to find the mass of the second object. Using the formula of gravitational force as follows :

$F=\dfrac{Gm_1m_2}{r^2}\\\\m_2=\dfrac{Fr^2}{Gm_1}\\\\m_2=\dfrac{2\times (45)^2}{6.67\times 10^{-11}\times 6.2}\\\\m_2=9.79\times 10^{12}\ kg$

So, the mass of the second object is $9.79\times 10^{12}\ kg$

6 0

3 years ago

Need help with two physics questions!

nikitadnepr [17]

1) The north component of the airplane velocity is 260 km/h.

2) The direction of the plane is $24^{\circ}$ north of east.

Explanation:

In this problem, we have to resolve the velocity vector into its components.

Taking east as positive x-direction and north as positive y-direction, the components of the velocity along the two directions are given by:

$v_x = v cos \theta$

$v_y = v sin \theta$

where

v is the magnitude of the velocity

$\theta$ is the angle between the direction of the velocity and the positive x-axis (the east direction)

For the airplane in this problem,

v = 750 km/h

$\theta=20^{\circ}$

So, the two components are

$v_x = (750)(cos 20)=704.8 km/h$

$v_y = (750)(sin 20)=256.5 km/h$

So, the component in the north direction is 256.5 km/h, so approximately 260 km/h.

In this problem, we have to use vector addition.

In fact, the motion of the plane consists of two displacements:

- A first displacement of 220 km in the east direction

- A second displacement of 100 km in the north direction

Using the same convention of the same problem (x = east and y = north), we can write

$d_x = 220 km$

$d_y = 100 km$

Since the two vectors are perpendicular to each other, we can find their magnitude using Pythagorean's theorem:

$d=\sqrt{d_x^2+d_y^2}=\sqrt{(220)^2+(100)^2}=241.7 km$

And the direction is given by

$\theta=tan^{-1}(\frac{d_y}{d_x})=tan^{-1}(\frac{100}{220})=24^{\circ}$ north of east.

Learn more about vectors here:

brainly.com/question/2678571

brainly.com/question/4945130

brainly.com/question/2678571

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

8 0

4 years ago