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3 years ago

Through which substance will sound travel the fastest? A)Copper wires B)Sea water C)Hot air D)Cold air

Physics

1 answer:

Papessa [141]3 years ago

3 0

Answer:

A. Copper wires

Explanation:

the the answer is copper wires because sound waves travel the slowest through gases, faster through liquids, and fastest through solids and copper wire is a solid.

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Two long, parallel wires are separated by a distance of 2.50 cm. The force per unit length that each wire exerts on the other is

Kisachek [45]

Answer:

The current in the second wire is 8.33 A and the two currents are flowing in the opposite directions

Explanation:

Given that,

The separation between two long parallel wires, d = 2.5 cm

The force per unit length that each wire exerts on the other is, $\dfrac{F}{l}=4\times 10^{-5}\ N/m$

The current in one wire, $I_1=0.6\ A$

(a) The force per unit length of the wire is given by :

$\dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi r}$

On putting all the values we get :

$4\times 10^{-5}=\dfrac{4\pi \times 10^{-7}\times 0.6I_2}{2\pi \times (2.5\times 10^{-2})}$

$I_2=8.33\ A$

So, the current in the second wire is 8.33 A.

(b) It is given that, both the wires repel each other, so the current in other wire is flowing in the opposite direction of the current in the first wire.

Hence, this is the required solution.

6 0

3 years ago

How is gravity simulated on the hermes spacecraft?

gulaghasi [49]

Hermes has a rotating wheel, or centrifuge, to provide artificial gravity for the crew. Spaceships in “2001: A Space Odyssey” and “Mission to Mars” were similarly equipped. Although it is not shown in the film, the astronauts would have used a Mars descent vehicle (MDV) to get down from Hermes to the surface.

3 0

3 years ago

Gold is used to make a super thin layer on the visors of astronauts' helmets because of which property in particular?

8090 [49]

B, because gold is the most malleable substance of all.

7 0

3 years ago

Read 2 more answers

The suspension system of a 1700 kg automobile "sags" 7.7 cm when the chassis is placed on it. Also, the oscillation amplitude de

spin [16.1K]

Answer:

the spring constant k = $5.409*10^4 \ N/m$

the value for the damping constant $\\ \\b = 1.518 *10^3 \ kg/s$

Explanation:

From Hooke's Law

$F = kx\\\\k =\frac{F}{x}\\\\where \ F = mg\\\\k = \frac{mg}{x}\\\\given \ that:\\\\mass \ of \ each \ wheel = 425 \ kg\\\\x = 7.7cm = 0.077 m\\\\g = 9.8 \ m/s^2\\\\Then;\\\\k = \frac{425 \ kg * 9.8 \ m/s^2}{0.077 \ m}\\\\k = 5.409*10^4 \ N/m$

Thus; the spring constant k = $5.409*10^4 \ N/m$

The amplitude is decreasing 37% during one period of the motion

$e^{\frac{-bT}{2m}}= \frac{37}{100}\\\\e^{\frac{-bT}{2m}}= 0.37\\\\\frac{-bT}{2m} = In(0.37)\\\\\frac{-bT}{2m} = -0.9943\\\\b = \frac{2m(0.9943)}{T}\\\\b = \frac{2m(0.9943)}{\frac{2 \pi}{\omega}}\\\\b = \frac{m(0.9943) \ ( \omega) )}{ \pi}$

$b = \frac{m(0.9943)(\sqrt{\frac{k}{m})}}{\pi}\\\\b = \frac{425*(0.9943)(\sqrt{\frac{5.409*10^4}{425}) } }{3.14}\\\\b = 1518.24 \ kg/s\\\\b = 1.518 *10^3 \ kg/s$

Therefore; the value for the damping constant $\\ \\b = 1.518 *10^3 \ kg/s$

5 0

3 years ago

A car acceleration uniformly from 5 m\s to 13m/s in 4.0s. What is the acceleration of the car

mel-nik [20]

Answer:

2m/s²

Explanation:

a=(v-u)/t

=(13-5)/4

=8/4=2m/s²

7 0

3 years ago