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Kitty [74]
3 years ago
10

How would Newton's Three laws apply to a Ferris Wheel?

Physics
1 answer:
Cloud [144]3 years ago
5 0
The Central pedal force of the wheels center is opposed by an equal force from the objects being spun around by the wheel
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This is a question on my physics test :)
Licemer1 [7]

Answer:

119.6 J/Kg°C

Explanation:

Data obtained from the question include:

Mass of substance (ms) = 170 g

Initial temperature of substance (Ts) = 120 °C

Volume of water = 200 mL

Initial temperature of water (Ts) = 10 °C

Temperature of the mixture (T2) = 12.6 °C

Density of water = 1 g/mL

Specific heat capacity of water (Cw) = 4200J/Kg°C

Specific heat capacity of substance (Cs) =..?

Next, we shall determine the mass of water. This can be obtained as follow:

Volume of water = 200 mL

Density of water = 1 g/mL

Mass of water =..?

Density = mass /volume

1 = mass /200

Cross multiply

Mass of water = 1 x 200

Mass of water = 200 g

Convert 200 g of water to Kg

Mass of water = 200/1000 0.2 Kg

Mass of water = 0.2 Kg

Now, we obtained the specific heat capacity of the substance using the following formula:

MwCw(T2 – Tw) + MsCs(T2 – Ts) = 0

Mass of water = 0.2 Kg

Initial temperature of water (Ts) = 10 °C

Specific heat capacity of water (Cw) = 4200J/Kg°C

Temperature of the mixture (T2) = 12.6 °C

Mass of substance (ms) = 170 g = 170/1000 = 0.17 Kg

Initial temperature of substance (Ts) = 120 °C

Specific heat capacity of substance (Cs) =..?

MwCw(T2 – Tw) + MsCs(T2 – Ts) = 0

0.2× 4200(12.6 – 10) + 0.17×Cs×(12.6 – 120) = 0

840(2.6) + 0.17Cs(– 107.4) = 0

2184 – 18.258Cs = 0

Rearrange

2184 = 18.258Cs

Divide both side by the coefficient of Cs i.e 18258

Cs = 2184/18.258

Cs = 119.6 J/Kg°C

Therefore, the specific heat capacity of the substance is 119.6 J/Kg°C

7 0
2 years ago
The ph balance is maintained by which organ?
Lena [83]
The Kidneys And Lungs.
7 0
3 years ago
Allison has been diagnosed with interstitial cystitis. Which treatment is her doctor likely to recommend?
Basile [38]

Answer: C) Sacral nerve stimulation

Explanation: interstitial cystitis can be simply refered to as a non infectious painful bladder condition which may be chronic depending on the severity. Some of the symptoms include pelvic and bladder pain as well as an urge to frequently urinate.

The best treatment that Allison's doctor is likely to recommend to her is the sacral nerve stimulation. Reducing the urgency to urinate which is associated with interstitial cystitis is the main target of this nerve stimulation technique, it involves simulating the sacral nerves which are the primary link between the spinal cord and nerves in the bladder. In this technique, electrical impulses are sent to the bladder by a thin wire which will be placed near the sacral nerves, this will help to reduce some of the symptoms.

6 0
3 years ago
Electronic flash units for cameras contain a capacitor for storing the energy used to produce the flash. In one such unit, the f
gladu [14]

Answer:

A) energy to be stored = 354.4J

B) capacitance = 0.0454 farad

Explanation:

Detailed explanation and calculation is shown in the image below

8 0
2 years ago
I need help again!!!!!! Due today!!!! NO LINK PLEASE
Elden [556K]

Answer:

The Acceleration of the object = 6.4 m/s²

<u>Explanation:</u>

Mass of block (m) = 5 kg

Action force on block, (F₁) = 40 N

<u>To Find:</u>

Acceleration of the object (a) = ?

<u>Required solution:</u>

Frictional force opposing the motion (F₂) = 8 N

Here in this question we have to find Acceleration of the object. So, firstly we have to find Net force of block after that we will find Acceleration of the object on the basis of conditions given above

⇒ Net force = Action force on block - Opposing friction force

⇒ F = F₁ - F₂

⇒ F = 40 - 8

⇒ F = 32 N

Now, we have to two elements that used in formula, Net force and Mass of block.

Net force of the block (F) = 32 N

Mass of block (m) = 5 kg

And we have to find Acceleration of the object.

We can find Acceleration of the object by using the Second law of Newton which says F = ma

Here,

F is the Force in N.

m is the Mass in kg.

a is the Acceleration in m/s².

So let's find Acceleration (a) !

† From second law of Newton

⇛ F = ma

⇛ a = F/m

⇛ a = 32/5

⇛ a = 6.4 m/s²

4 0
2 years ago
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