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4 years ago

How would Newton's Three laws apply to a Ferris Wheel?

1 answer:

5 0

The Central pedal force of the wheels center is opposed by an equal force from the objects being spun around by the wheel

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You are climbing in the High Sierra when you suddenly find yourself at the edge of a fog-shrouded cliff. To find the height of t

s344n2d4d5 [400]

Answer:

Height with sound ignored = Gravity x Time taken = 9.8 x 8.60 = 84.28 meters

Time taken by the sound = 84.28/330 = 0.255 seconds

Height with sound involved = (84.28 x 0.255) + 84.28 = 105.80 meters

a. Underestimated

5 0

3 years ago

Neptune has a mass that is about 17 times the mass of Earth. The distance between the Sun and Neptune is about 30.1 times the di

marshall27 [118]

Answer: 0.0187 times the force between Sun and Earth.

The gravitational force between two massive bodies is directly proportional to their masses and inversely proportional to the square of distance between them.

$F=G\frac {M_1M_2}{d^2}$

where G is the gravitational constant.

Let,

The mass of the Sun be $M_S$

The mass of the Earth be $M_E$

The mass of the Neptune be $M_N$

The Distance between Sun and Earth be $d_{SE}$

The Distance between Sun and Neptune be $d_{NE}$

It is given that the mass of Neptune is 17 times mass of Earth.

$\Rightarrow M_N=17M_E$

The distance of Neptune from Sun is 30.1 times the distance of Earth from Sun.

$\Rightarrow D_{SN}=30.1D_{SE}$

The Force between Earth and Sun is $F_{SE}=3.5\times10^{28}N$

The Force between Neptune and Sun:

$F_{SN}=G\frac{M_SM_N}{D_{SN}^2}=G\frac{M_S17M_E}{(30.1D_{SE})^2}=\frac {17}{30.1^2}G\frac{M_SM_E}{D_{SE}^2}=\frac {17}{30.1^2}F_{SE}=0.0187F_{SE}$

5 0

3 years ago

Read 2 more answers

Which vector below goes from (0,0) to (4,1)?

Lesechka [4]

Explanation:

Please attach the figure next to your question in order to help you.. Wish u the best and Have a great Day. Good Luck!

8 0

4 years ago

If the 78.0 kg astronaut were in a spacecraft 6R from the center of the earth, what would the astronaut's weight be on earth? 76

den301095 [7]

(a) 764.4 N

The weight of the astronaut on Earth is given by:

$F=mg$

where

m is the astronaut's mass

g is the acceleration due to gravity

Here we have

m = 78.0 kg

g = 9.8 m/s^2 at the Earth's surface

So the weight of the astronaut is

$F=(78.0)(9.8)=764.4 N$

(b) 21.1 N

The spacecraft is located at a distance of

$r=6R$

from the center of Earth.

The acceleration due to gravity at a generic distance r from the Earth's center is

$g=\frac{GM}{r^2}$

where G is the gravitational constant and M is the Earth's mass.

We know that at a distance of r = R (at the Earth's surface) the value of g is 9.8 m/s^2, so we can write:

$GM=9.8R^2$ (1)

the acceleration due to gravity at r=6R instead will be

$g'=\frac{GM}{(6R)^2}$

And substituting (1) into this formula,

$g'=\frac{9.8R^2}{36R^2}=0.27 m/s^2$

So the weight of the astronaut at the spacecratf location is

$F'=mg'=(78.0 kg)(0.27 m/s^2)=21.1 N$

6 0

3 years ago

IE is the energy required to remove an electron from an atom. As atomic radius increases, the valence electrons get farther from

Bond [772]

Answer:

The bigger the atom the lesser the ability of the atom to hold on to its valence electrons.

Explanation:

Atomic radius can be looked at as the distance between the nucleus and the outermost energy level. As an atom gets bigger, the outer shell gets further and further from the positive nucleus. this means that electrons that are in the outer energy level become less held (attracted) by the nucleus because of distance and shielding of the attractive forces by the electrons in the lower energy levels. This means that as an atom becomes bigger, its ability to hold on to its outer electrons lessens.

4 0

3 years ago