Answer:
first do:
60mph * 4 hours= 240mi
Let D = the distance the passenger train has to
travel to catch the freight train
Start a stopwatch when the passenger train leaves
Let t = the time on the stopwatch when they meet
Equation for freight train:
d-240=60t
Equation for passenger train:
d=100t
all together:
100t-240=60t
we can do 100t-60t because they both have (t)= 40t
40t=240 *now divide 240 by 40= 6
THEN do:
D= 100mph x 6= 600mi
They will meet 600 mi from the station
to check:
d-240=60t x 6
600-240= 360
60 x 6= 360
360=360
Answer:
12
Step-by-step explanation:
12 because that's how many dots/vertices are shown(sorry if im wrong)
Answer:
Equation have Unique solution i.e 
Step-by-step explanation:
Given Equation:

Solving the Equation for 'x'.

Adding '
' both sides:

Adding '42' both sides:


The equation have Unique solution with the value of 
<h3>
Answer: Choice C) 31</h3>
==============================================
Explanation:
The recursive rule
f(n+1)=f(n)-3
can be rearranged to
f(n) = f(n+1)+3
after adding 3 to both sides
----------------
Now let's say we plug in n = 3
f(n) = f(n+1)+3
f(3) = f(3+1)+3
f(3) = f(4)+3
f(3) = 22+3
f(3) = 25
Repeat for n = 2
f(n) = f(n+1)+3
f(2) = f(2+1)+3
f(2) = f(3)+3
f(2) = 25+3
f(2) = 28
Each time we keep adding 3 to get the previous term (since the original recursive rule says to subtract 3 to get the next term; we just go backwards of what the instructions say).
Lastly, we can find that f(1) = f(2)+3 = 28+3 = 31 making the answer to be choice C.
In order to solve for this question, let's assign a couple variables.
The variable 't' will represent the number of two-point questions, and the variable 's' will represent the number of six point questions.
From the given, we can already form two equations:
t + s = 36
("An exam... contains 36 questions")
2t + 6s = 148
("An exam worth 148 points... Some questions are worth 2 points, and the others are worth 6 points")
Before we begin calculating anything, we can simplify the second equation we made, since all the numbers are divisible by 2:
2t + 6s = 148
t + 3s = 74
Now let's refer back to the first equation. We can subtract both sides by 's' (you could also subtract both sides by 't', but I personally think that this will make solving the equation less difficult):
t + s = 36
t = 36 - s
This effectively gives us a value for the variable 't'. We can assign this value back into our first equation:
t + 3s = 74
(36 - s) + 3s = 74
36 + 2s = 74
2s = 38
s = 19
Input 's' into our second equation to solve for 't':
t = 36 - s
t = 36 - 19
t = 17
There are 17 two-point questions and 19 six-point questions
- T.B.