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3 years ago

How do you write a ratio as a fraction in lowest terms

Mathematics

1 answer:

sp2606 [1]3 years ago

4 0

I found this online hope it helps

1 foot is 12 inches, so 2 feet are 24 inches.

The ratio is therefore 24/52. However, you're asked to have the lowest terms fraction, so let's look at common factors:

24 = 2*2*2*3

52 = 2*2*13.

The two numbers share a common factor of 4, so divide by 4 on both sides of the equation for success:

24/52 = 6/13.

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What is (0.7)*(0.4)

zhuklara [117]

(0.7)(0.4)=0.28 because 7×4 is 28 and you just add a 0

4 0

3 years ago

Read 2 more answers

he isosceles triangle has a perimeter of 7.5 m. Which equation can be used to find the value of x if the shortest side, y, measu

lapo4ka [179]

Answer:

2x+ 2.1 = 7.5

x=2.7

Step-by-step explanation:

The perimeter of an isosceles triangle with sides x and y is

2x+y = P

I put y as the single side since the question said y is the shortest side. It should say shorter sides if the two sides with the same length are smaller than the third.

We know y =2.1 and P = 7.5

Substituting these values in, we get

2x+ 2.1 = 7.5

Subtract 2.1 from each side

2x+2.1 -2.1 = 7.5 -2.1

2x= 5.4

Divide each side by 2

2x/2 = 5.4/2

x = 2.7 m

3 0

3 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

4. Five cards are randomly chosen from a deck of 52 (13 denominations with 4 suits). a. How many ways are there to receive 5 car

yan [13]

Answer:

There are 2,598,960 ways to receive 5 cards from a deck of 52.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

a. How many ways are there to receive 5 cards from a deck of 52?

$C_{52,5} = \frac{52!}{5!(47)!} = 2598960$

There are 2,598,960 ways to receive 5 cards from a deck of 52.

4 0

2 years ago

I am not sure how to do this −(−2−5x)+(−2)=18

aivan3 [116]

(2+5x)-2=18
2+5x-2=18
5x=18

x=18/5= 3.6

4 0

2 years ago

Read 2 more answers