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Svetach [21]
2 years ago
9

Help meeeeeeeeeeeeee

Mathematics
2 answers:
makvit [3.9K]2 years ago
6 0

Answer:

the family free skate

Step-by-step explanation:

Brrunno [24]2 years ago
4 0
fourth option is the answer
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The equation of line WX is y = −2x − 5. Write an equation of a line perpendicular to line WX in slope-intercept form that contai
densk [106]

Answer:

third option

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 2x - 5 ← is in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-2} = \frac{1}{2} , then

y = \frac{1}{2} x + c ← is the partial equation

To find c substitute (- 1, 1) into the partial equation

1 = - \frac{1}{2} + c ⇒ c = 1 + \frac{1}{2} = \frac{3}{2}

y = \frac{1}{2} x + \frac{3}{2} ← equation of perpendicular line

7 0
3 years ago
Hi can u guys help me pla
nevsk [136]

Answer:

yes

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Type the correct answer in each box. Use numbers instead of words. The cost of cereal is proportional to the number of ounces. C
lisov135 [29]

Answer:

Step-by-step explanation:

To find the cost per ounce, divide the cost by the number of ounces. The cost is $2.72 and the number of ounces is 16, so the cost per ounce is $2.72/16 = 0.17. Multiply the cost per ounce by the amount asked to calculate for, 0.17 x 28 = $4.76

To conclude, the cost of 28 ounces of cereals is $4.76.

5 0
1 year ago
Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i
Vsevolod [243]

\huge \boxed{\mathfrak{Answer} \downarrow}

\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\

Multiply both numerator and denominator of \sf \frac{5-3i}{-2-9i} \\ by the complex conjugate of the denominator, -2+9i.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)})  \\

Multiplication can be transformed into difference of squares using the rule: \sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}})  \\

By definition, i² is -1. Calculate the denominator.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85})  \\

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85})  \\

Do the multiplications in \sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right).

\large \bf \: Re(\frac{-10+45i+6i+27}{85})  \\

Combine the real and imaginary parts in -10+45i+6i+27.

\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85})  \\

Do the additions in \sf-10+27+\left(45+6\right)i.

\large \bf Re(\frac{17+51i}{85})  \\

Divide 17+51i by 85 to get \sf\frac{1}{5}+\frac{3}{5}i \\.

\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i)  \\

The real part of \sf \frac{1}{5}+\frac{3}{5}i \\ is \sf \frac{1}{5} \\.

\large  \boxed{\bf\frac{1}{5} = 0.2} \\

3 0
3 years ago
Also the same as the other problem
irakobra [83]

Answer:

30-60-90

Step-by-step explanation:

A 30-60-90 triangle is a right angled triangle

Please mark it as brainliest if it helped

Answered by Gauthmath

5 0
3 years ago
Read 2 more answers
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