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natima [27]
3 years ago
14

What is the relationship between the 4s in the number 4498

Mathematics
2 answers:
algol133 years ago
7 0
The 4 in the thousands place is 10 times the 4 in the hundreds place.
kodGreya [7K]3 years ago
5 0
<span>One 4 is in the hundreds place and the other is in the thousands place. So that's your answer</span>
You might be interested in
What is the y value of the vertex 4x^2+8x-8
Oksana_A [137]

Answer:

The y-value of the vertex is -12

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

f(x)=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

In this problem we have

f(x)=4x^{2}+8x-8 -----> this a vertical parabola open upward

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)+8=4x^{2}+8x

Factor the leading coefficient

f(x)+8=4(x^{2}+2x)

Complete the square. Remember to balance the equation by adding the same constants to each side

f(x)+8+4=4(x^{2}+2x+1)

f(x)+12=4(x^{2}+2x+1)

Rewrite as perfect squares

f(x)+12=4(x+1)^{2}

f(x)=4(x+1)^{2}-12

The vertex is the point (-1,-12)

The y-value of the vertex is -12

5 0
3 years ago
Read 2 more answers
Mary is 5 years older than bob. If the sum of their ages is 39 write and solve an equation to find ages. Please help me with a c
nikdorinn [45]
5x=39 x stands for the age of bob so 39/5 =7.8 which is rounded up to 8 and if you multiply 8 by 5 you get 40 but if you multiply 7.8 by 5 you get 39 so his age would be 7.8 years old.
4 0
3 years ago
Read 2 more answers
He sum of 4x and 2x is less than the difference of 5x and 13
Nata [24]
4x + 2x< 5x-13
solve
6x < 5x-13
subtract 5x
x< (-13)
3 0
3 years ago
Need help ASAP !!! And show work please
sammy [17]

Answer:

\sqrt{40} or 6.32

Step-by-step explanation:

We can find the distance between two points by using this formula

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

where the x and y values are derived from the given points

The points given are ( -2 , 5 ) and ( 4 , 3 )

So we plug in the x and y values of those coordinates into the distance formula

\sqrt{(4-(-2)^2+(3-5)^2} \\4-(-2)=6\\3-5=-2\\d=\sqrt{6^2+-2^2} \\6^2=36\\-2^2=4\\36+4=40\\d=\sqrt{40}

or 6.32

6 0
3 years ago
Assessments.momaxcom student
Lady_Fox [76]

Answer:

$0.19

Step-by-step explanation:

8 0
3 years ago
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