Answer:
The words from parsley are PAR, YES, RAP, PAY,and SLAP
The words from pepper are PEEP and that is it
Step-by-step explanation:
Answer:
∠x = 90°
∠y = 58°
∠z = 32°
Step-by-step explanation:
he dimensions of the angles given are;
∠B = 32°
Whereby ΔABC is a right-angled triangle, and the square fits at angle A, we have;
∠A = 90°
∠B + ∠C = 90° which gives
32° + ∠C = 90°
∠C = 58°
∠x + Interior angle of the square = 180° (Sum of angles on a straight line)
∠x + 90° = 180°
∠x = 90°
∠x + ∠y + 32° = 180° (Sum of angles in a triangle)
90° + ∠y + 32° = 180°
∠y = 180 - 90° - 32° = 58°
∠y + ∠z + Interior angle of the square = 180° (Sum of angles on a straight line)
58° + ∠z +90° = 180°
∴ ∠z = 32°
∠x = 90°
∠y = 58°
∠z = 32°
I really don’t understand this question. can you explain this in the comment so i can answer your
To solve this problem, we must first find the discount amount, and then subtract this amount from the total price of the item.
To find the discount amount, we must find 35% of $40. To do this, we must first convert 35% to its decimal equivalent by dividing 35/100. We do this because percentages are parts out of a total 100 percent, thus this fraction represents an equivalent value that we can multiply by other numbers. Using our knowledge that 35/100 = 0.35, we can now set up our expression:
35% of $40 (keep in mind that the word "of" refers to multiplication in math)
0.35 * 40
To solve, we just multiply these two numbers together, which gives us 14.
This means that Kala got a discount of $14 off of the original price of $40. To find out how much she paid for it, we must subtract $14 from $40, as modeled below:
$40 - $14 = $26
Therefore, Kala paid $26 for the item.
Hope this helps!
Answer:
your answer is correct
Step-by-step explanation:
4b² + 8b + 3
Consider the factors of the product of the coefficient of the b² term and the constant term which sum to give the coefficient of the b- term.
product = 4 × 3 = 12 and sum = + 8
The factors are 2 and 6
Use these factors to split the b- term
4b² + 2b + 6b + 3 ( factor the first/second and third/fourth terms )
= 2b(2b + 1) + 3(2b + 1) ← factor out (2b + 1) from each term
= (2b + 1)(2b + 3)
