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2 years ago

8

Which model is 85% shaded? Done

2 answers:

Kobotan [32]2 years ago

8 0

Answer:

I would need to see the models to answer this question.

pshichka [43]2 years ago

3 0

Answer:

?

Step-by-step explanation:

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Match each object with the characteristics it represent

Aleks [24]

We need the object and the characteristics.

6 0

3 years ago

What is the coefficient of the x5y5-term in the binomial expansion of (2x – 3y)10? 10C5(2)5(3)5 10C5(2)5(–3)5 –10C5(2)5(–3)5 10C

butalik [34]

ANSWER

$10C_5(2)^{5}( - 3)^5$

EXPLANATION

The given binomial expansion is:

${(2x - 3y)}^{10}$

Compare this to

${(a + b)}^{n}$

we have a=2x , b=-3y and n=10

We want to find the coefficient of the term

${x}^{5} {y}^{5}$

This implies that, r=5.

The terms in the expansion can be obtained using

$T_{r+1}=nC_ra^{n-r}b^r$

We substitute the given values to obtain;

$T_{5+1}=10C_5(2x)^{10-5}( - 3y)^5$

$T_{6}=10C_5(2x)^{5}(3y)^5$

$T_{6}=10C_5(2)^{5}( - 3)^5 {x}^{5} {y}^{5}$

Hence the coefficient is;

$10C_5(2)^{5}( - 3)^5$

5 0

3 years ago

Read 2 more answers

What is <br> 30% of 120 <br><br> I Really want to get it right because the POSSIBLE POINTS: (25)

Blizzard [7]

Answer:

the answer is 36

hope i helped

6 0

3 years ago

Read 2 more answers

Will reward brainliest!

Lina20 [59]

Option D: Two irrational solutions

Explanation:

The equation is $17+3 x^{2}=6 x$

Subtracting 6x from both sides, we have,

$3x^{2} -6x+17=0$

Solving the equation using quadratic formula,

$x=\frac{6 \pm \sqrt{36-4(3)(17)}}{2(3)}$

Simplifying the expression, we get,

$\begin{aligned}x &=\frac{6 \pm \sqrt{36-204}}{6} \\&=\frac{6 \pm \sqrt{-168}}{6} \\&=\frac{6 \pm 2 i \sqrt{42}}{6}\end{aligned}$

Taking out the common terms and simplifying, we have,

$\begin{aligned}x &=\frac{2(3 \pm i \sqrt{42})}{6} \\&=\frac{(3 \pm i \sqrt{42})}{3}\end{aligned}$

Dividing by 3, we get,

$x=1+i \sqrt{\frac{14}{3}}, x=1-i \sqrt{\frac{14}{3}}$

Hence, the equation has two irrational solutions.

8 0

3 years ago

Need to write steps and solve <br> thanks

nalin [4]

<u>Answer:</u>

The coordinates of endpoint V is (7,-27)

<u>Solution:</u>

Given that the midpoint of line segment UV is (5,-11) And U is (3,5).

To find the coordinates of V.

The formula for mid-point of a line segment is as follows,

Midpoint of UV is $\frac{x_{1}+x_{2}}{2}$ , $\frac{y_{1}+y_{2}}{2}$

As per the formula, $\frac{x_{1}+x_{2}}{2}$ =5, $\frac{y_{1}+y_{2}}{2}$ =-11

Here $x_{1}=3; y_{1}=5$

Substituting the value of $x_{1}$ we get,

$\frac{3+x_{2}}{2}$ =5

$3+x_{2}=5\times2$

$x_{2}=10-3$

$x_{2}=7$

Substituting the value of $x_{2}$ we get,

$\frac{5+y_{2}}{2}$ =-11

$5+y_{2}=-11\times2$

$y_{2}=-22-5$

$y_{2}=-27$

So, the coordinates of V is (7,-27)

7 0

3 years ago