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IgorLugansk [536]
3 years ago
8

A person wishes to mix coffee worth nine dollars per pound with coffee worth three dollars per pound to get 240 pounds of a mixt

ure worth five dollars per pound how many pounds of the nine dollars and the three dollar coffee will be needed
Mathematics
1 answer:
Anastasy [175]3 years ago
4 0
\bf \begin{array}{lccclll}
&amount&price&priced\ amount\\
&-----&-----&--------\\
\textit{9 bucks/lb}&x&9&9x\\
\textit{3 bucks/lb}&y&3&3y\\
-----&-----&-----&-------\\
mixture&240&5&1200
\end{array}
\\\\\\
\begin{cases}
x+y=240\implies \boxed{y}=240-x\\
9x+3y=1200\\
----------\\
9x+3\left( \boxed{240-x} \right)=1200
\end{cases}

solve for "x".

what about "y"? well, y = 240 - x
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Step-by-step explanation:

The information provided is:

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Compute the total cost per card as follows:

Total cost per card = Cost of the paper + Cost of printing

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\text{Optimal probability}=\frac{\text{Profit}}{\text{Profit+Loss}}

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Use Excel's NORMSINV{0.907} function to find the Z-score.

<em>z</em> = 1.322

Compute the optimal production quantity for the card as follows:

\text{Optimal Production Quantity}=\text{Total Demand}+(z\times SD_{\text{total demand}}) \\

                                               =8000+(1.322\times 1000)\\=8000+1322\\=9322

Thus, the optimal production quantity is 9,322 cards.

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