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3 years ago

Mary travelled 70 miles/hour due north. This is an example of what?

Physics

2 answers:

Kobotan [32]3 years ago

6 0

Answer:

velocity.

Explanation:

Velocity is a vector quantity, which consists of:

- a magnitude, which is equal to the ratio between the displacement of an object and the time taken for the displacement to occur:

$v=\frac{d}{t}$

- a direction, which is equal to the direction of the displacement

In this case, we are given both the magnitude (70 miles/hour) and the direction (north), so this is an example of velocity.

kolezko [41]3 years ago

4 0

I believe this would be an example of Mary's velocity. We have her speed and direction which is all you need to find velocity.

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Two immersion heaters, A and B, are both connected to a 120.0-V supply. Heater A can raise the temperature of 1.00 L of water fr

Inessa05 [86]

Answer:

Ratio of resistance of heater A to resistance of heater B is 5.80

Explanation:

Consider C be the specific heat of water, R₁ and R₂ be the resistance of heater A and heater B respectively.

Given:

Mass of water in heater A, m₁ = 1 L

Mass of water in heater B, m₂ = 5.80 L

Initial temperature, T₀ = 20 ⁰C

Final temperature, T₁ = 90 ⁰C

Time, t = 5 min

Amount of heat required to raise the temperature of water by heaters A and B are given by:

Q₁ = m₁C(T₁ - T₀) and

Q₂ = m₂C(T₁ - T₀)

Ratio of power used by both the heaters A and B is:

$\frac{P_{1} }{P_{2} } =\frac{Q_{1} }{t} \times\frac{t}{Q_{2} }$

Since, time t, temperature difference(T₁ - T₀) and specific heat C are same for both the heaters A and B. So, the above equation becomes:

$\frac{P_{1} }{P_{2} } =\frac{m_{1} }{m_{2} }$ ...(1)

The relation to determine electrical power for both heaters A and B are:

$P_{1}=\frac{V^{2} }{R_{1} }$ and

$P_{2}=\frac{V^{2} }{R_{2} }$

Here V is the voltage applied to both the heaters and is equal.

So, the ratio of electrical power of heaters is:

$\frac{P_{1} }{P_{2} } =\frac{R_{2} }{R_{1} }$ ....(2)

But according to the problem, the electrical power is converted into the thermal power. So,equation (1) and (2) are equal. Hence,

$\frac{m_{1} }{m_{2} } =\frac{R_{2} }{R_{1} }$

Substitute the suitable values in the above equation.

$\frac{1 }{5.80 } =\frac{R_{2} }{R_{1} }$

$\frac{R_{1} }{R_{2} }=5.80$

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3 years ago

Which equations represent the relationship between wavelength and frequency for a sounds wave

ioda

Waves can be described using a number of different characteristics of a wave. Wavelength and frequency are two such characteristics. The relationship between wavelength and frequency is that the frequency of a wave multiplied by its wavelength gives the speed of the wave

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3 years ago

Two ropes support a load of 478 kg. The two ropes are perpendicular to each other, and the tension in the first rope is 2.2 time

sveta [45]

Answer:

T₂ = 1937.68 N

Explanation:

First, we will calculate the weight of the object:

$W = mg = (478\ kg)(9.81\ m/s^2)\\W = 4689.18\ N$