Question

Calculate the wavelength of the electromagentic waves with the given frequencies, and determine the type of electromagnetic radiation for each combination. frequency: 4.38×1014 Hz wavelength : m type frequency: 4.14×1020 Hz wavelength : m type frequency: 3.24×1012 Hz wavelength : m type

Answer 1

To develop this problem we require the concepts related to wavelength and its expression to calculate it.

The wavelength is given by

$\lambda =\frac{c}{f}$

Where,

$c=3*10^8 m/s$ light velocity

f = frequency.

Our values are given by,

$f_1=4.38*10^{14}Hz$

$f_2= 4.14*10^{20}Hz$

$f_3 = 3.24*10^{12}Hz$

Then,

$\lambda_1=\frac{3*10^8}{4.38*10^{14}}= 6.8493*10^{-7}m$ Visible

$\lambda_2=\frac{3*10^8}{4.14*10^{20}}= 7.24*10^{-13}m$ Gamma Ray

$\lambda_3=\frac{3*10^8}{3.24*10^{12}}= 9.259*10^{-5}m$ Infrared

*Note the designation on the type of rays that are, can be found in consulted via On-line or in the optical books referring to the electromagnetic spectrum table with their respective ranges.