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Dovator [93]
3 years ago
7

Which energy transformations occur when a candle burns

Physics
2 answers:
gayaneshka [121]3 years ago
6 0
The heat from the wick melts the wax which gets absorbed in the wick and then gets burnt (which is really oxidation) to produce heat energy<span> as well as light </span>energy. The energy<span> transforms from chemical </span>energy<span> to heat and light </span>energy<span>. Because when the </span>candle burns<span> a chemical reaction </span>occurs<span>, and produces heat and light.

</span>
ELEN [110]3 years ago
5 0
A candle burning produces heat energu and light energy; the wax gets melted which creates both heat and light. I hope this helped Enjoy the rest of your day!!!!!!!!!!!!
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A mass weighing pounds is attached to a spring whose constant is lb/ft. The medium offers a damping force that is numerically eq
andreyandreev [35.5K]

Answer:

hello your question has some missing values attached below is the complete question with the missing values

answer :

a) 0.083 secs

b) 0.33 secs

c)  3e^-4/3

Explanation:

Given that

g = 32 ft/s^2 ,  spring constant ( k ) = 2 Ib/ft

initial displacement = 1 ft above equilibrium

mass = weight / g = 4/32 = 1/8

damping force = instanteous velocity  hence  β = 1

a<u>)Calculate the time at which the mass passes through the equilibrium position.</u>

time mass passes through equilibrium = 1/12 seconds = 0.083

<u>b) Calculate the time at which the mass attains its extreme displacement </u>

time when mass attains extreme displacement = 1/3 seconds = 0.33 secs

<u>c) What is the position of the mass at this instant</u>

position = 3e^-4/3

attached below is the detailed solution to the given problem

6 0
3 years ago
6. Draw a velocity-time graph for an object originally traveling at -3 m/s. The object
faltersainse [42]

See the graph in attachment

Explanation:

In this problem we have to draw a velocity-time graph for an object travelling initially at -3 m/s, then slowing down and turning around.

In the graph, we see that the initial velocity at time t = 0 is

v_0 = -3 m/s

and it is negative, so below the x-axis.

Later, the object slows down: this means that the magnitude of its velocity increases, therefore (since the velocity is negative) the curve must go upward, approaching and reaching the x-axis (which corresponds to zero velocity).

After that, the object's velocity keep increasing, but now it is positive: this means that the object is travelling in a direction opposite to the initial direction, so it has turned around.

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

4 0
3 years ago
A beam of light passes through a liquid into air. Angle 1, angle of
Ede4ka [16]

Answer: 1.57

Explanation:

This described situation is known as Refraction, a phenomenon in which light bends or changes its direction when passing through a medium with a index of refraction different from the other medium.  

In this context, the index of refraction is a number that describes how fast light propagates through a medium or material.  

According to Snell’s Law:  

n_{1}sin(\theta_{1})=n_{2}sin(\theta_{2}) (1)  

Where:  

n_{1} is the first medium index of refraction (the value we want to know)

n_{2}=1 is the second medium index of refraction (air)  

\theta_{1}=23\° is the angle of incidence

\theta_{2}=38\° is the angle of refraction

Now, let's find n_{1} from (1):

n_{1}=n_{2}\frac{sin \theta_{2}}{sin \theta_{1}} (2)  

Substituting the known values:

n_{1}=1\frac{sin(38\°)}{sin(23\°)}  

Finally:

n_{1}=1.57  

3 0
3 years ago
A particle with kinetic energy equal to 282 J has a momentum of magnitude 26.4 kg · m/s. Calculate the speed (in m/s) and the ma
masha68 [24]

Answer:

v=21.36\,\,\frac{m}{s}\\

m=1.2357\,\,kg

Explanation:

Recall the formula for linear momentum (p):

p = m\,v  which in our case equals 26.4 kg m/s

and notice that the kinetic energy can be written in terms of the linear momentum (p) as shown below:

K=\frac{1}{2} m\,v^2=\frac{1}{2} \frac{m^2\,v^2}{m} =\frac{1}{2}\frac{(m\,v)^2}{m} =\frac{p^2}{2\,m}

Then, we can solve for the mass (m) given the information we have on the kinetic energy and momentum of the particle:

K=\frac{p^2}{2\,m}\\282=\frac{26.4^2}{2\,m}\\m=\frac{26.4^2}{2\,(282)}\,kg\\m=1.2357\,\,kg

Now by knowing the particle's mass, we use the momentum formula to find its speed:

p=m\,v\\26.4=1.2357\,v\\v=\frac{26.4}{1.2357} \,\frac{m}{s} \\v=21.36\,\,\frac{m}{s}

4 0
3 years ago
Does ice melt faster in water or air
STALIN [3.7K]

Answer:

ice melts faster in water

5 0
3 years ago
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