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mart [117]
3 years ago
13

Gravity on Earth is 9.8 m/s^2, and gravity on Jupiter is 23.1 m/s^2. So, if the mass of a rock is 70 kilograms, it's weight on E

arth is____newtons and its weight on Jupiter is____newtons?
Physics
2 answers:
Levart [38]3 years ago
3 0
~686newtons on earth and
~1617 newtons on jupiter
the formula is weight = gravitational acceleration * mass of the object
prohojiy [21]3 years ago
3 0

Answer:

686 N, 1617 N

Explanation:

Gravity on earth, ge = 9.8 m/s^2

Gravity on Jupiter, gj = 23.1 m/s^2

m = 70 kg

Weight on earth, We = m x ge = 70 x 9.8 = 686 N

Weight on Jupiter, Wj = m x gj = 70 x 23.1 = 1617 N

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A car is moving 14.4 m/s. It decelerates at -1.55 m/s^2 for 4.26 s. It then accelerates at 1.83 m/s^2 until it reaches 11.8 m/s.
Aleonysh [2.5K]

The total time is 6.45 s

Explanation:

The motion of the car is a uniformly accelerated motion, so we can use suvat equations.

In the first part,

u_1 = 14.4 m/s (initial velocity)

a_1 = -1.55 m/s^2 (acceleration)

t_1=4.26 s (time of the first part)

So, we can find the velocity of the car after the first part, by using

v_1 = u_1 +a_1 t_1 =14.4+(-1.55)(4.26)=7.8 m/s

This is therefore the initial velocity of the second part:

u_2 = v_1 = 7.8 m/s

a_2 = 1.83 m/s^2 (acceleration in the second part)

v_2 = 11.8 m/s (final velocity)

And therefore,

v_2 = u_2 + a_2 t_2\\t_2=\frac{v_2-u_2}{a_2}=\frac{11.8-7.8}{1.83}=2.19 s

So, the total time is

t=t_1+t_2=4.26+2.19=6.45 s

Learn more about uniformly accelerated motion:

brainly.com/question/9527152

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brainly.com/question/2506873

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7 0
3 years ago
Which statement(s) about neutrons is/are TRUE?
sergey [27]
The answer is A and B


Explanation: the nucleus was viewed as composed of combinations of protons and electrons, the two elementary particles known at the time, but that model presented several experimental and theoretical contradictions.

AND

Protons and neutrons have approximately the same mass, about 1.67 × 10-24 grams.



4 0
3 years ago
A graph that plots the temperature of a star against its brightness.
Ostrovityanka [42]

Answer:

C. HertzPrung Russel Diagram

Explanation:

The Hertzsprung–Russell diagram, or H–R diagram, is a plot of stellar luminosity against surface temperature. Most stars lie on the main sequence, which extends diagonally across the H–R diagram from high temperature and high luminosity to low temperature and low luminosity.

5 0
3 years ago
Suppose that Earth’s axis were tilted 90 degrees instead of 23.5 degrees. What might the seasons be like?
irga5000 [103]
The seasons basically wouldn't change, because basically only one spot would be facing directly at the sun the whole time, so it would be summer there forever, and the edges that barely get any sun would be in eternal winter.
6 0
3 years ago
Read 2 more answers
Our Sun shines bright with a luminosity of 3.828x10^26 Watt. Her energy is responsible for many processes and the habitable temp
Sav [38]

Answer:

(a) 1317.44 W/m²

(b) 1.74×10¹⁵ litres of heating oil

(c) -20.63°C

(d) Energy storage in the Earth and the air

Explanation:

The parameters given are;

Luminosity of the Sun = 3.828 × 10²⁶ Watt

Distance of the Earth from the Sun, d = 152.06 × 10⁶ km

The radius of the Sun = 696 × 10³ km

The radius of the Earth, r_E = 6730 km

The surface area of the Sun = 12000 × Surface area of the Earth

The surface area of the Sun = 6.09 × 10¹² km²

Cross sectional area of the Earth = 1.27 × 10⁴ m² = 0.0127 km²

By the inverse square law, we have;

R = \dfrac{Luminosity \, of \, the \, Sun}{4 \pi d^2}

Where:

R = Solar radiation reaching the Earth

Therefore;

R = \dfrac{3.828 \times 10^{26}}{4 \times \pi \times (1.5206 \times 10^{11})^2} = 1317.44 \ W/m^2

Hence, the energy, E, reaching the Earth in a day is given as follows;

E = R × 4×π×r_E²×60×60×24 = 1317.44 × 4 × π × 6730000² × 60×60×24

E = 6.479×10²² Joules

(b) The number of litres of heating oil is therefore;

6.479×10²² J ÷ (37.3×10⁶ J/litre) = 1.74×10¹⁵ litres of heating oil

(c) 30% of the Energy is reflected, therefore;

0.7 × 6.479×10²² Joules = 4.54×10²² Joules reaches the Earths surface

From Stefan-Boltzmann law, we have;

T = \left (\dfrac{\left (1 - \alpha  \right ) \times R }{4\times \sigma }   \right )^{\dfrac{1}{4}}

Where:

α = 0.3

σ = Stefan-Boltzmann constant = 5.6704×10⁻⁸ W/(m²·K⁴)

Therefore;

T = \left (\dfrac{\left (1 - 0.3 \right ) \times 1317.44 }{4\times 5.6704 \times 10^{-8} }   \right )^{\dfrac{1}{4}} = 252.52 \ K = -20.63 ^{\circ} C

(d) The heat storage in the Earth and the air

7 0
3 years ago
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