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maxonik [38]
3 years ago
12

Factor completely 6x²-4x -2

Mathematics
2 answers:
swat323 years ago
7 0
6x^2-4x -2 \\ \\ GCF = 2 \\ \\ 2( \frac{6x^2}{2} +  \frac{-4x}{2} -  \frac{2}{2} \ / \ factor \ out \ GCF \\ \\ 2(3x^2 - 2x - 1) \ / \ simplify \ terms \\ \\ 2(3x^2 + x - 3x - 1) \ / \ factor \\ \\ 2(x(3x+1) - (3x + 1)) \ / \ factor \ out \ common \ terms \\ \\ 2(3x+1)(x - 1) \ / \ factor \ out \ common \ term \\ \\ Answer: \fbox {2 (3x + 1)(x - 1)}
Murljashka [212]3 years ago
5 0
6x² - 4x - 2
2(3x²) - 2(2x) - 2(1)
2(3x² - 2x - 1)
2(3x² - 3x + x - 1)
2(3x(x) - 3x(1) + 1(x) - 1(1))
2(3x(x - 1) + 1(x - 1))
2(3x + 1)(x - 1)
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Find the value of x which ABCD must be a parallellogram?<br> x =
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3 years ago
Answer question 4 pls for math
brilliants [131]

Answer:

Rule: y = 2x

m = 2

b = 0

Step-by-step explanation:

(17, 34) and (22, 44)

<u>Slope:</u>

m=(y2-y1)/(x2-x1)

m=(44-34)/(22-17)

m= (10)/5

m = 2

<u>Slope-intercept:</u>

y - y1 = m(x - x1)

y - 34 = 2(x - 17)

y - 34 = 2x - 34

y = 2x

y = mx + b

y = 2x

b = 0

3 0
2 years ago
How to solve this problem
ANTONII [103]

Answer:

B: (2, -1)

Step-by-step explanation:

1) First isolate the y in both equations

2) Set the equations equal to each other

3) Solve for x (you should get 2 and 5)

4) Insert the x values back in to get your y values

5) You should have gotten (2, -1) and (5, 2)

These are your two answers, but the question is only asking for one solution and (5,2) isn't one of the options, so it has to be (2,-1).

8 0
3 years ago
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