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3 years ago

Factor completely 6x²-4x -2

2 answers:

swat323 years ago

7 0

$6x^2-4x -2 \\ \\ GCF = 2 \\ \\ 2( \frac{6x^2}{2} + \frac{-4x}{2} - \frac{2}{2} \ / \ factor \ out \ GCF \\ \\ 2(3x^2 - 2x - 1) \ / \ simplify \ terms \\ \\ 2(3x^2 + x - 3x - 1) \ / \ factor \\ \\ 2(x(3x+1) - (3x + 1)) \ / \ factor \ out \ common \ terms \\ \\ 2(3x+1)(x - 1) \ / \ factor \ out \ common \ term \\ \\ Answer: \fbox {2 (3x + 1)(x - 1)}$

Murljashka [212]3 years ago

5 0

6x² - 4x - 2
2(3x²) - 2(2x) - 2(1)
2(3x² - 2x - 1)
2(3x² - 3x + x - 1)
2(3x(x) - 3x(1) + 1(x) - 1(1))
2(3x(x - 1) + 1(x - 1))
2(3x + 1)(x - 1)

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How many lines of symmetry does an isosceles triangle have

timofeeve [1]

Answer: 1

Step-by-step explanation: can only be split evenly by one line.

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3 years ago

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Sarah is carrying out a series of experiments which involve using mcreasing amounts of a chemical. In the

Marianna [84]

Sarah is carrying out a series of experiments which involve using increasing amounts of a chemical. In the first experiment she uses 6g of the chemical and in the second experiment she uses 7.8 g of the chemical

(i)Given that the amounts of the chemical used form an arithmetic progression find the total amount of chemical used in the first 30 experiments

(ii)Instead it is given that the amounts of the chemical used for a geometric progression. Sarah has a total of 1800 g of the chemical available. Show that the greatest number of experiments possible satisfies the inequality: $1.3^N \leq 91$ and use logarithms to calculate the value of N.

Answer:

(a)963 grams

(b)N=17

Step-by-step explanation:

(a)

In the first experiment, Sarah uses 6g of the chemical

In the second experiment, Sarah uses 7.8g of the chemical

If this forms an arithmetic progression:

First term, a =6g

Common difference. d= 7.8 -6 =1.8 g

Therefore:

Total Amount of chemical used in the first 30 experiments

$S_n=\dfrac{n}{2}[2a+(n-1)d] \\S_{30}=\dfrac{30}{2}[2*6+(30-1)1.8] \\=15[12+29*1.8]\\=15[12+52.2]\\=15*64.2\\=963$ grams$

Sarah uses 963 grams in the first 30 experiments.

(b) If the increase is geometric

First Term, a=6g

Common ratio, r =7.8/6 =1.3

Sarah has a total of 1800 g

Therefore:

Sum of a geometric sequence

$S_n=\dfrac{a(r^N-1)}{r-1} \\1800=\dfrac{6(1.3^N-1)}{1.3-1} \\1800=\dfrac{6(1.3^N-1)}{0.3}\\$Cross multiply\\1800*0.3=6(1.3^N-1)\\6(1.3^N-1)=540\\1.3^N-1=540\div 6\\1.3^N-1=90\\1.3^N=90+1\\1.3^N=91$

Therefore, the greatest possible number of experiments satisfies the inequality

$1.3^N \leq 91$

Next, we solve for N

Changing $1.3^N \leq 91$ to logarithm form, we obtain:

$N \leq log_{1.3}91\\N \leq \dfrac{log 91}{log 1.3}\\ N \leq 17.19$

Therefore, the number of possible experiments, N=17

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3 years ago

Which of the following statements is correct? (Everfi)

Likurg_2 [28]

My best guess would be d.

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3 years ago

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Angle E has what measurement according to the protractor?

oksian1 [2.3K]

Answer:

Angle E has $120\°$

Step-by-step explanation:

we know that

Observing the figure, according to the protractor

Angle B has $30\°$

Angle C has $50\°$

Angle D has $90\°$

Angle E has $120\°$

Angle F has $140\°$

5 0

3 years ago

B. If some amount of water contains 1400 oxygen atoms, how many hydrogen atoms does it contain?

Genrish500 [490]

Answer:

B: 2800 hydrogen atoms

C: 6760 hydrogen atoms

D: y=amount of oxygen atoms*2

Step-by-step explanation:

B: We know the formula for water is H2O. SO that means that there is 2 hydrogen atoms and 1 oxygen atom. So there is 2 times the amount of hydrogen atoms so we can do 1400*2=2800, So there is 2800 hydrogen atoms in the water.

C: Same thing as B. 3380*2=6760

D: y=amount of oxygen atoms*2. Because there is one oxygen atom and two hydrogen atoms so 1*2=2.

5 0

3 years ago