Answer:
23. 
24. 
25. 
26. 
27. 
28. 
Step-by-step explanation:
To solve these i used SOHCAHTOA
23.
Find the missing side using Tangent
24.
Find the missing side using Tangent
25.
Find the missing side using Tangent
26.
Find the missing side using Tangent
27.
Find the missing side using Tangent
28.
Find the missing side using Tangent
Answer: 8 pounds 10 ounces
Step-by-step explanation:
7 ± 1 ⇒ 8
2 ± 8 ⇒ 10
⇒ 8 pounds 10 ounces
Answer:
6 and 0
Step-by-step explanation:
When we have f(-3) and f(6), that means we plug -3 and 6 in for x to solve for f(x):
f(-3) = (-2/3) * (-3) + 4 = 2 + 4 = 6
f(6) = (-2/3) * 6 + 4 = -4 + 4 = 0
The answers are thus 6 and 0.
y - y_{1} = m(x-x_{1} )\\
y - (2) = \frac{2}{3} (x - (-1))
y - 2 = \frac{2x}{3} + \frac{2}{3}
y = \frac{2x}{3} + \frac{2}{3} + 2
y = \frac{2x}{3} + \frac{8}{3}[/tex]
y = 2x/3 + 8/3
Answer:
Position of the particle is 20.
Step-by-step explanation:
Position function is integration of velocity function.
Velocity function is integration of acceleration function.
So, let's integrate the given a(t) to get v(t)
If we integrate v(t) then we get s(t)
It is given the values of s(0) =0 and s(1)=20
So, position of the particle is difference of 20, 0. That's 20-0 =20.
