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nignag [31]
3 years ago
14

X – 4x < 5x + 16 solve for x

Mathematics
1 answer:
Margaret [11]3 years ago
3 0

Answer:

x>-2

Step-by-step explanation:

x-4x<5x+16

Subtract 5x from both sides:

x-4x-5x<16

Combine like terms:

-8x<16

Divide both sides by 8:

-x<2

Divide both sides by -1:

x>-2

Hope this helps!

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D-10-2d+7=8+d-10-3d
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Solution,solve\:for\:d,\:d-10-2d+7=8+d-10-3d\quad :\quad d=1

Steps:

d-10-2d+7=8+d-10-3d

\mathrm{Subtract\:}d-10\mathrm{\:from\:both\:sides},\\d-10-2d+7-\left(d-10\right)=8+d-10-3d-\left(d-10\right)

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\mathrm{The\:Correct\:Answer\:is\:d=1}

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\mathrm{-Austint1414}

4 0
3 years ago
Question 4 Given: f(x) = -3x – 3 and g(x) = x2 + 5 Find (f - g) ().​
Aleonysh [2.5K]

Answer:

We get \mathbf{(f-g)(x)= -x^2-3x-8}

Step-by-step explanation:

We are given:

f(x) = -3x - 3\\ g(x) = x^2 + 5

We need to find (f-g)(x) (assuming there is x in the bracket, i.e. (f - g) () should be (f-g)(x))

We would simply subtract f(x) and g(x)

(f-g)(x)\\= -3x-3-(x^2+5)\\Multiply\:minus\:sign\:with\:terms\:inside\:the\:bracket\\=-3x-3-x^2-5\\Combining\:like\:terms:\\=-x^2-3x-3-5\\=-x^2-3x-8

So, We get \mathbf{(f-g)(x)= -x^2-3x-8}

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