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suter [353]
3 years ago
11

Which values of a and b make the equation true? (2xy)^4 ---------- =4x^a (y^b) 4xy

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
7 0

Answer:

B) a = 3, b = 3 .

Step-by-step explanation:

Given : (2xy)^{4} = 4x^{a} (y^{b})4xy.

To find : Which values of a and b make the equation true.

Solution : We have given that (2xy)^{4} = 4x^{a} (y^{b})4xy.

By exponential  same base rule :x^{n} x^{m} = x^{m+n} if base are same then power will be add.

2^{4} x^{4} y^{4} = 16x^{a+1} y^{b+1}.

Solving exponent

16x^{4} y^{4} =  16x^{a+1} y^{b+1}.

On equating x variable

x^{4} =  x^{a+1}.

By exponent rule : if x^{m} =  x^{n} then m =n.

So, 4 = a+1

On subtracting by 1 both sides

a = 3.

On equating y variable ,

4 = b+1

On subtracting by 1 both sides

b = 3 .

Therefore, B) a = 3, b = 3 .

hoa [83]3 years ago
5 0
(2xy)^4=4x^a(y^b)4xy
16x^4y^4=16x^(a+1)y^(b+1)
4=a+1 4=b+1
3=a 3=b

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