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3 years ago

Number 13 please!!!!!!!!!!!

Physics

1 answer:

atroni [7]3 years ago

4 0

'A' and 'C' both show that behavior.

'D' also shows it, but the object is moving backwards when time begins.
First it moves faster and faster backwards, then it moves slower and slower backwards.

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e force acting between two charged particles A and B is 5.2 × 10-5 newtons. Charges A and B are 2.4 × 10-2 meters apart. If the

anastassius [24]

The force acting between the particles is

$F=k \frac{Q_{1}Q_{2}}{r^2}$
Then
$Q_{2}= \frac{5.2 \times 10^-^5 \times 0.024^2}{ 9.0 \times 10^9 7.2 \times 10^-^8} =4.622 \times 10^-^1^1C$

7 0

2 years ago

Read 2 more answers

Of all the radio waves, these have the shortest wavelengths and the the highest frequency?

Julli [10]

If by chance you mean any wave, the wave with the shortest wavelength/highest frequency is gamma rays.

4 0

2 years ago

Two particles are moving along the x axis. Particle 1 has a mass m₁ and a velocity v₁ = +4.7 m/s. Particle 2 has a mass m₂ and a

nirvana33 [79]

Answer:

m₁ / m₂ = 1.3

Explanation:

We can work this problem with the moment, the system is formed by the two particles

The moment is conserved, to simulate the system the particles initially move with a moment and suppose a shock where the particular that, without speed, this determines that if you center, you should be stationary, which creates a moment equal to zero

p₀o = m₁ v₁ + m₂ v₂

pf = 0

m₁ v₁ + m₂ v₂ = 0

m₁ / m₂ = -v₂ / v₁

m₁ / m₂= - (-6.2) / 4.7

m₁ / m₂ = 1.3

Another way to solve this exercise is to use the mass center relationship

Xcm = 1/M (m₁ x₁ + m₂ x₂)

We derive from time

Vcm = 1/M (m₁ v₁ + m₂v₂)

As they say the velocity of the center of zero masses

0 = 1/M (m₁ v₁ + m₂v₂)

m₁ v₁ + m₂v₂ = 0

m₁ / m₂ = -v₂ / v₁

m₁ / m₂ = 1.3

4 0

2 years ago

Determine the rate at which the electric field changes between the round plates of a capacitor, 8.0 cm in diameter, if the plate

Daniel [21]

Solution:

The relation between the potential difference and the electric field between the plates of the parallel plate capacitor is given by :

$E=\frac{V}{D}$

Differentiating on both the sides with respect to time, we get

$\frac{dE}{dt}=\frac{1}{D}\frac{dV}{dt}$

Therefore, the rate of the electric field changes between the plates of the parallel plate capacitor is given by :

$\frac{dE}{dt}=\frac{1}{D}\frac{dV}{dt}$

$=\frac{1}{1.4 \times 10^{-3}} \times 110$

$=7.85 \times 10^4$ V/m-s

8 0

2 years ago

Một đoạn mạch gồm R1=8 ôm;R2=12 ôm.biết R1 nối tiếp với đoạn mạch gồm R2 song song với R3; R3=1/2 R2 cường độ dòng điện chạy qua

LUCKY_DIMON [66]

Answer:

Explanation:

b. R3= 1/2R2=6 ôm

R12= R1+R2=20 ôm

Rtđ=R12.R3/R12+R3= 4,62 ôm

c. U= I.Rtđ = 2.4,62=9,23 V

I1=I2= 9,23/20= 0,4615 A

I3= 2-0,4615=1,5385 A

7 0

2 years ago