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melisa1 [442]
3 years ago
15

Number 13 please!!!!!!!!!!!

Physics
1 answer:
atroni [7]3 years ago
4 0
'A' and 'C' both show that behavior.

'D' also shows it, but the object is moving backwards when time begins.
First it moves faster and faster backwards, then it moves slower and slower backwards.
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The coefficient of static friction is 0.222

Explanation:

In order for the car to remain in circular motion, the frictional force must be able to provide the necessary centripetal force. Therefore, the car will start skidding when the two forces are equal:

\mu mg=m\frac{v^2}{r}

where the term on the left is the frictional force, while the term on the right is the centripetal force, and where

\mu is the coefficient of static friction

m is the mass of the car

g is the acceleration of gravity

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In this problem, we have:

r = 564 m

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And re-arranging the equation for \mu, we can find the coefficient of static friction:

\mu = \frac{v^2}{gr}=\frac{35^2}{(9.8)(564)}=0.222

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5 0
3 years ago
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BARSIC [14]

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Answer:

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