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storchak [24]
4 years ago
9

A 20g book laying on a 40cm high table. Just before a cat knocks it off the table what is the books gravitational potential ener

gy?
Physics
1 answer:
disa [49]4 years ago
3 0

Answer:

The book gravitational potential energy is 0.0784 Joules.

Explanation:

Given:

Mass of book, m = 20 g = 20 ÷ 1000 = 0.02 kg

Table height,   h = 40 cm =40 ÷ 100 = 0.4 m

To Find:

Gravitational Potential Energy = ?

Solution:

Gravitational Potential Energy :

Gravitational potential energy is energy an object possesses because of its position in a gravitational field.

Formula is given by

\textrm{Gravitational Potential Energy}= m\times g\times h

Where,

m = mass

g = acceleration due to gravity = 9.8 m/s²

h = height

Substituting the values we get

\textrm{Gravitational Potential Energy}= 0.02\times 9.8\times 0.4\\\\\textrm{Gravitational Potential Energy}=0.0784 Joules

The book gravitational potential energy is 0.0784 Joules.

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An olympic sprinter can go from a state of rest to 11 meters per second in 10 seconds. What is the sprinter's average accelerati
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Answer:  Sprinter's average acceleration =  1.1\frac{m}{s^2}

Explanation:

The formula for the average acceleration is given as follows:

\overline{a} = \frac{v_f - v_i}{\Delta t} --- (A)

Where,

v_f = Final velocity = 11\frac{m}{s}

v_i = Initial velocity = 0\frac{m}{s}

\Delta t = Elapsed time = 10 seconds

Plug the values in equation (A):

\overline{a} = \frac{11 - 0}{10} = 1.1\frac{m}{s^2}


Therefore, the sprinter's average acceleration is 1.1\frac{m}{s^2}.


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3 years ago
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An accelerometer is a device that uses the extension of a spring to measure acceleration in terms of Earth's gravitational accel
Aloiza [94]

letter B for plato is correct!!

8 0
3 years ago
the thermometer has its stem marked in millimeter instead of degree Celsius. the lower fixed point is 30mm and the upper fixed p
Lorico [155]

10°c

Explanation:

Given parameter;

Lower fixed point = 30mm

Upper fixed point = 180mm

Reading = 45mm

Unknown:

The degree celcuis temperature at 45mm = ?

Solution:

To solve this problem we simply compare the mm- scale to the celcius - scale that we know.

The upper fixed point is the boiling point of water

Lower fixed point is the freezing point of water

This shows that both the upper and lower fixed point of both thermometers are the same;

         mm-scale          °c scale

          180mm               100°c

            45mm                x

          30mm                  0°c

Solving;

                     \frac{x - 0}{100 -0} =  \frac{45 - 30 }{180- 30}

   x (150) = 100  x 15

   x = 10°c

learn more:

Temperature scales brainly.com/question/1603430

#learnwithBrainly

 

7 0
4 years ago
Inez uses hairspray on her hair each morning before going to school. The spray spreads out before reaching her hair partly becau
Tamiku [17]

Answer:

7.0\cdot 10^{-13}C

Explanation:

The magnitude of the electrostatic force between two charged objects is

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the separation between the two charges

The force is attractive if the charges have opposite sign and repulsive if the charges have same sign.

In this problem, we have:

r=0.070 cm =7\cdot 10^{-4} m is the distance between the charges

q_1=q_2=q since the charges are identical

F=9.0\cdot 10^{-9}N is the force between the charges

Re-arranging the equation and solving for q, we find the charge on each drop:

F=\frac{kq^2}{r^2}\\q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(9.0\cdot 10^{-9})(7\cdot 10^{-4})^2}{8.99\cdot 10^9}}=7.0\cdot 10^{-13}C

8 0
3 years ago
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