Because no perfect squares are factors of 37, the most simplified that the square root of 37 can get is
√37, or approximately 6.08
Answer:
a) 0.6032
b)
Lower limit: 0.48
Upper limit: 0.72
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Question a:
In a random sample of 63 professional actors, it was found that 38 were extroverts.
We use this to find the sample proportion, which is the point estimate for p. So

Question b:
Sample of 63 means that 
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

Rounding to two decimal places:
Lower limit: 0.48
Upper limit: 0.72
Surface area of the fig is 2350.9 sq m (approx).
Step-by-step explanation:
Given,
Diameter = 34 m
so, radius (r) = 17 m
Height of the cylinder (h) = 12 m
Slant height of the cone (l) = 20 m
To find the surface area of the fig
Surface area of the fig = surface area of cylinder + surface area of cone
Formula
Surface area of cylinder = 2πrh
Surface area of cone = πrl
So,
Surface area of cylinder = 2π×17×12 sq m = 408π sq m
Surface area of cone = π×17×20 = 340π sq m
Surface area of the fig = 408π+340π sq m = 748π sq m
= 2350.9 sq m (approx)
The answer is: "
" .
________________________________________________Explanation:________________________________________________(1/6) / (3/7 hr) = x/ 1 hr ;
→ (1/6) / (3/7) = x ;
↔ (1/6) / (3/7) = x ;
→ (1/6) * (7/3) = x ;
The "3" cancels to a "1", and<span /> the "6" cancels to a "2" ;
→ { since: " 6 ÷ 3 = 2" ; and since: " 3 ÷ 3 = 1 "} ;
_____________________________________________________→ And we can rewrite as:
→ (1/2) * (7/1) = (1 * 7) / (2 * 1)
= 7/2 ;
_____________________________________________________The answer is: "
" .
_____________________________________________________<u>Note</u>: The question asks, "At this rate, what "FRACTION" of the distance...?" ;
→ As such, we leave the answer in the "fraction" form.
_____________________________________________________