Answer:
[- 4, ∞ )
Step-by-step explanation:
the expression inside the radical must be greater than or equal to zero
x +4 ≥ 0 ⇔ x ≥ - 4
domain: x ∈ [- 4, ∞ )
Answer:
..............I think its wrong .......
<u>Answer-</u>
<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>
<u>Solution-</u>
The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.
For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.
Here we are given the three vertices of the triangle are J(-4,-1), K(-4,8) and L(2,8)
If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.
Applying distance formula we get,

As,




Therefore, the vertex at K (-4, 8) is the orthocentre.
Answer: x = -3
Step-by-step explanation:
2y + x = -15
y = 2x
2y = 2(2x) = 4x
4x + x = -15
5x = -15
x = -3
Answer:
The amount of money he owes when he begins making payments:
A = 13000 x ( 1 + rate/12)^month
= 13000 x (1 + (3.6/100)/12)^15
= 13597.45 dollar
Hope this helps!
:)