How to find the sum of 2+4+6....+40?
1 answer:
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Since molly's solution tally's with the given solution, hence <em>Molly's solution is correct.</em>
Given the working on a partial product of 93 and 51 carried out by Molly as shown:
This partial product can also be solved as shown below:
Applying the distributive law:
Since molly's solution tally's with the given solution, hence <em>Molly solution is correct.</em>
Learn more about partial product at: brainly.com/question/24716925
First of all, you add 1/3 and 4/5, so you get:
To add 2 fractions, they need to have the same denominator. Since 3 and 5 don't have a common factor, so you multiply 1/3 by 5, and 4/5 by 3, so you get:
Now, the two fractions got the same denominator, and you can add them by adding the numerators over the same denominator. (You don't add denominators in addition) so you get:
That's the sum of 1/3 + 4/5.
Now, they want the sum of the 2 fractions 7 times. So you multiply 17/15 by 7. And as you know, 7 = 7/1. So you get:
In multiplication no need to have the same denominator. You multiply nominators by nominators and denominators by denominators. So you get:
Since 119 and 15 don't have a common factor, so they can't be simplified.
So, the answer is 119/15.
Hope this Helps! :D
To add 2 fractions, they need to have the same denominator. Since 3 and 5 don't have a common factor, so you multiply 1/3 by 5, and 4/5 by 3, so you get:
Now, the two fractions got the same denominator, and you can add them by adding the numerators over the same denominator. (You don't add denominators in addition) so you get:
That's the sum of 1/3 + 4/5.
Now, they want the sum of the 2 fractions 7 times. So you multiply 17/15 by 7. And as you know, 7 = 7/1. So you get:
In multiplication no need to have the same denominator. You multiply nominators by nominators and denominators by denominators. So you get:
Since 119 and 15 don't have a common factor, so they can't be simplified.
So, the answer is 119/15.
Hope this Helps! :D
Answer:
16 meters
Step-by-step explanation:
The height function is given by:
The value of x, in seconds, for which the derivate of the height function is zero, is the time at which the maximum height occurs:
For x = 3 seconds, the height is:
The maximum height that the ball will reach is 16 meters.