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Studentka2010 [4]
3 years ago
11

Given the line a 6x+y=5 give an example of an equation of a line that would be parallel

Mathematics
1 answer:
Rzqust [24]3 years ago
7 0
X = 1 & Y = -1 this is the way that we should find x
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a port and a radar station are 2 mi apart on a straight shore running east and west. a ship leaves the port at noon traveling no
Rom4ik [11]

Answer:

The rate of change of the tracking angle is 0.05599 rad/sec

Step-by-step explanation:

Here the ship is traveling at 15 mi/hr north east and

Port to Radar station = 2 miles

Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles

Therefore the ship, port and radar makes a triangle with sides

2, 7.5 and x

The value of x is gotten from cosine rule as follows

x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04

x = 6.25 miles

By sine rule we have

\frac{sin A}{a} = \frac{sin B}{b}

Therefore,

\frac{sin 45}{6.25} = \frac{sin \alpha }{7.5}

α = Angle between radar and ship α

∴ α = 58.052

Where we put

\frac{sin 45}{6.25} = \frac{sin \alpha }{x} to get

\frac{x}{6.25} = \frac{sin \alpha }{sin 45} and differentiate to get

\frac{\frac{dx}{dt} }{6.25} = cos\alpha\frac{\frac{d\alpha }{dt}  }{sin 45}

\frac{15sin45 }{6.25cos\alpha } =\frac{d\alpha }{dt}  }= 3.208 degrees/second = 0.05599 rad/sec.

6 0
3 years ago
This is you not me tehehaha
Usimov [2.4K]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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Zohar is using scissors to cut a rectangle with a length of 5x – 2 and a width of 3x + 1 out of a larger piece of paper. Which e
sweet-ann [11.9K]

Answer with Step-by-step explanation:

Zohar cut a rectangle with a length of 5x – 2

and a width of 3x + 1

We know that:

Perimeter of rectangle is:

Perimeter=2(length+width)

                =2(5x-2+3x+1)

                =2(8x-1)

                =16x-2

Hence, expression which can be used to find the perimeter of the rectangle is:

16x-2

Now, when x=4

16x-2=16×4-2

        =62

Hence, when x=4 ,Perimeter=62

4 0
3 years ago
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Help please <br><br><br> 12345678910<br><br> 12345678910
Vlada [557]

Answer:

4743246

Step-by-step explanation:

7 0
3 years ago
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If the density of the full can is 1.2 g/cc what is the mass ?
Natali5045456 [20]
Mass=Density*Volume
Density=1.1 g/cc
Volume of a cylinder: <span>π*r^2*h
</span>Radius of the top of the can: 3.57
Volume of this can: 480.47
480.47*1.1=528.517
If I'm correct the mass of this can should be 528.517 
4 0
3 years ago
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