No,
0.5=0.50 >0.25
......................
<span>1) Find the equation of the
line that passes through (x1, y1) and (x3, y3).
We have it: </span>y = 0.4x + 38<span>2) Find the equation of the
line parallel to the previous line that passes through (x2, y2).
</span><span>That is: y = 0.4x + 59
</span><span>3) Find the weighted
average of the
y-intercepts. b=(b1+b2+b1)/3 = (38+59+38)/3
b= 45
The median-median line is the line parallel to the previous two lines with the weighted y-intercept.Hence, Y = 0.4 x + 45 is the answer</span>
Answer:
a) p-hat (sampling distribution of sample proportions)
b) Symmetric
c) σ=0.058
d) Standard error
e) If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).
Step-by-step explanation:
a) This distribution is called the <em>sampling distribution of sample proportions</em> <em>(p-hat)</em>.
b) The shape of this distribution is expected to somewhat normal, symmetrical and centered around 16%.
This happens because the expected sample proportion is 0.16. Some samples will have a proportion over 0.16 and others below, but the most of them will be around the population mean. In other words, the sample proportions is a non-biased estimator of the population proportion.
c) The variability of this distribution, represented by the standard error, is:
d) The formal name is Standard error.
e) If we divided the variability of the distribution with sample size n=90 to the variability of the distribution with sample size n=40, we have:

If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).
Answer:
can you take a picture of the options?
Step-by-step explanation: