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inn [45]
3 years ago
5

Find the value of this expression if x=3

Mathematics
1 answer:
Anna [14]3 years ago
6 0

Answer:

6

Step-by-step explanation:

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Is 0.5 less than 0.25
Andrews [41]
No,

0.5=0.50 >0.25
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3 years ago
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Tracy is finding the equation of a median-median line. She found that the equation of the line through the first and third summa
rodikova [14]
<span>1) Find the equation of the line that passes through (x1, y1) and (x3, y3).
We have it: </span>y = 0.4x + 38<span>2) Find the equation of the line parallel to the previous line that passes through (x2, y2). 
</span><span>That is: y = 0.4x + 59
</span><span>3) Find the weighted average of the
y-intercepts.  b=(b1+b2+b1)/3 = (38+59+38)/3
                      b= 45
The median-median line is the line parallel to the previous two lines with the weighted y-intercept.Hence, Y = 0.4 x + 45 is the answer</span>
7 0
3 years ago
Help me with this problem please!!!! :)​
kifflom [539]

Answer:

this should do it

4 0
2 years ago
Repeated student samples. Of all freshman at a large college, 16% made the dean’s list in the current year. As part of a class p
Dima020 [189]

Answer:

a) p-hat (sampling distribution of sample proportions)

b) Symmetric

c) σ=0.058

d) Standard error

e) If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

Step-by-step explanation:

a) This distribution is called the <em>sampling distribution of sample proportions</em> <em>(p-hat)</em>.

b) The shape of this distribution is expected to somewhat normal, symmetrical and centered around 16%.

This happens because the expected sample proportion is 0.16. Some samples will have a proportion over 0.16 and others below, but the most of them will be around the population mean. In other words, the sample proportions is a non-biased estimator of the population proportion.

c) The variability of this distribution, represented by the standard error, is:

\sigma=\sqrt{p(1-p)/n}=\sqrt{0.16*0.84/40}=0.058

d) The formal name is Standard error.

e) If we divided the variability of the distribution with sample size n=90 to the variability of the distribution with sample size n=40, we have:

\frac{\sigma_{90}}{\sigma_{40}}=\frac{\sqrt{p(1-p)/n_{90}} }{\sqrt{p(1-p)/n_{40}}}}= \sqrt{\frac{1/n_{90}}{1/n_{40}}}=\sqrt{\frac{1/90}{1/40}}=\sqrt{0.444}= 0.667

If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

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3 years ago
#Homework Help Please
Snezhnost [94]

Answer:

can you take a picture of the options?

Step-by-step explanation:

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