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djverab [1.8K]
3 years ago
13

V=Bh over 3 for B=15 inches two squared .and h=28inches

Mathematics
1 answer:
Leni [432]3 years ago
3 0
Explain what u need help with cuz i think i know this

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Find area and perimeter of shaded regions below
aleksandrvk [35]

Answer:

Step-by-step explanation:

ABCD is a square.

side = 24 cm

Area of square = side  * side = 24 * 24 = 576 cm²

Semicircle:

d = 24 cm

r = 24/2 = 12 cm

Area of semi circle =πr²

                               = 3.14 * 12 * 12

                               = 452.16 cm²

Area of shaded region = area of square - area of semicircle  + area of semicircle

  = 576  - 452.16 + 452.16

  = 576 cm²

Perimeter:

Circumference of semicircle = 2πr

               = 2 * 3.14 * 12

               = 75.36

Perimeter = 2* circumference of semicircle + 24 + 24

                = 2 * 75.36 + 24 + 24

                = 150.72 + 24 + 24

                 = 198.72 cm

6 0
3 years ago
Please help me with this i will mark brainliest<br><br><br><br><br>QUICK!!!!!!
Yanka [14]

Answer:

w - 3.3 + -3.3 = 5.6 - 3.3

w = 2.3

3 0
3 years ago
What is 76.78 rounded to the nearest whole number?
galben [10]
Lets look at the number. 76.78. In each of the different place holders the number is higher than 5. Lets do some examples. 74 rounded to the nearest whole number is going to be 70. 76 rounded to the whole number will be 80. The .78 in your question also contributes. 

Answer: 80
6 0
3 years ago
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Lin needs to save up $20 for a new game. How much money does she have if she has saved 75% of her goal?
Nataly [62]

Answer: She has $15

Step-by-step explanation:

20*0.75=15

6 0
3 years ago
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Please help me gotta pass
Rudik [331]
Answer:

Y=59 Z=93

Explanation:

To find Z, you have to know the line is equal to 180 degrees. You then subtract 180-87=93 that’s how you get Z. Then with that you know that 34+Y is going to equal 93 because they are across from each other. I forgot what that property is called, but yeah. Then you subtract 93-34=59 there you go hope that helps :)
4 0
3 years ago
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