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3 years ago

Calculate using long division: ( x^4 +4x^3-3x^2-6x-7) divided by ( x^{2} -8)

Mathematics

1 answer:

sammy [17]3 years ago

3 0

The photo didn't come out as nice as I would have wanted; to be clear, the remainder is 18x + 33.

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A bike rental company charges a fee per hour. The charge, in dollars, is the same each hour. The ordered pairs (3, 13.50) and (5

olchik [2.2K]

If the function is y = 4.5x. Then the rate of change of the function expressed as a unit rate will be 4.5.

<h3>What is the linear system?</h3>

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

A bike rental company charges a fee per hour.

The charge, in dollars, is the same each hour.

The ordered pairs (3, 13.50) and (5, 22.50) represent the corresponding hours, x, and cost, y.

Then the linear equation is given as

$\begin{aligned} \rm y - 22.5 &= \rm \dfrac{22.5 - 13.5}{5 - 3} (x- 5)\\\\\rm y - 22.5 &= \rm 4.5x - 22.5\\\\\rm y &= \rm 4.5x \end$

Then the rate of change of the function expressed as a unit rate will be

$\rm \dfrac{dy}{dx} = \dfrac{d}{dx} (4.5x )\\\\\dfrac{dy}{dx} = 4.5$

More about the linear system link is given below.

brainly.com/question/20379472

#SPJ1

7 0

2 years ago

An instructor who taught two sections of engineering probability last term, the first with 20 students and thesecond with 30, de

Oliga [24]

Answer:

0.207

Step-by-step explanation:

This is an hypergeometric distribution problem

An hypergeometric distribution has the same sense as the discrete probabilities of binomial distribution, but unlike binomial distribution, hypergeometric distribution does not allow replacement.

Binomial distribution expresses the probability of picking k objects from n with replacement, but hypergeometric distribution expresses picking k objects from n without replacement, with the finite total population, N, containing K objects.

It is expressed mathematically as

h(k: n, K, N) = (ᴷCₖ)(ᴺ⁻ᴷCₙ₋ₖ)/(ᴺCₙ)

where

k = number of students in the 2nd section required to be in the first 15 graded projects (number of successes) = 10

n = total number of first graded projects (number of trials) = 15

K = number of students in the 2nd section of the class = 30

N = total number of students = 50

h(10: 15, 30, 50) = (³⁰C₁₀)(⁵⁰⁻³⁰C₁₅₋₁₀)/(⁵⁰C₁₅)

h(10: 15, 30, 50) = (³⁰C₁₀)(²⁰C₅)/(⁵⁰C₁₅)

= (30,045,015)(15,504)/(2,250,829,575,120)

P(X = 10) = 0.207

Hope this Helps!!!

7 0

2 years ago

Evaluateing expressions 9x-c

lyudmila [28]

Answer:

9x−c

= 9x + − c

=−c+9x

Step-by-step explanation:

3 0

2 years ago

Solve 3x-1 =2x+1 solve the question

galina1969 [7]

3x-1=2x+1

3x-2x = 1+1

x=2

8 0

2 years ago

Read 2 more answers

David bought a bag of candy that contains 300 pieces. He wants to split the bag among his 21 students. How many pieces of candy

solmaris [256]

Answer:

each student will receive 14 pieces of candy and that leaves 6 pieces for himself.

14*21=294

294+6=300

3 0

3 years ago

Read 2 more answers