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3 years ago

I need help please!!!!!!

Mathematics

2 answers:

diamong [38]3 years ago

8 0

Answer: pretty sure it is linear

Step-by-step explanation:

STatiana [176]3 years ago

3 0

Linear is the answer

For quadratic either the x or y would need to be raised to the 2nd power which they aren’t

Same for exponential ( no variables are raised to any exponent)

The are no brackets representing taking the absolute value of any variable so that can’t be right

You can always test a few values for x to graph the y result to see that in this case it does graph a line

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A florist is filling a large order for a client. The client wants no more than 300 roses in vases. The smaller vase will contain

d1i1m1o1n [39]

Answer:

$8x+12y\leq 300$

$x\geq 6$

$y\leq 12$

$x\geq 2y$

Step-by-step explanation:

We are given that

x=Number of small vases

y=Number of large vases

Total number of roses not more than 300 in vases.

Number of roses in small vase atleast=8

Number of roses in large vase not more than =12

We have to find the constraints are placed on the variables in the given situation.

According to question

$8x+12y\leq 300$

$x\geq 6$

$y\leq 12$

$x\geq 2y$

4 0

3 years ago

The amount of time devoted to studying statistics each week by students who achieve a grade of A in the course is a normally dis

svlad2 [7]

Answer:

a) 11.7% of students study for more than 10 hours per week.

b) 35.6% of student spends between 7 and 9 hours studying.

c) 1.6% of students spend fewer than 3 hours studying.

d) 5% of all A students spend studying 4.0455 or less hours during a week.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 7.5 hours

Standard Deviation, σ = 2.1 hours

We are given that the distribution of amount of time is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(students study for more than 10 hours per week)

P(x > 10)

$P( x > 10) = P( z > \displaystyle\frac{10 - 7.5}{2.1}) = P(z > 1.1904)$

$= 1 - P(z \leq 1.1904)$

Calculation the value from standard normal z table, we have,

$P(x > 10) = 1 - 0.883 = 0.117 = 11.7\%$

b) P(student spends between 7 and 9 hours studying.)

$P(7 \leq x \leq 9) = P(\displaystyle\frac{7 - 7.5}{2.1} \leq z \leq \displaystyle\frac{9-7.5}{2.1}) = P(-0.2380 \leq z \leq 0.7142)\\\\= P(z \leq 0.7142) - P(z < -0.2380)\\= 0.762 - 0.406 = 0.356 = 35.6\%$