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3 years ago

I need help please!!!!!!

Mathematics

2 answers:

diamong [38]3 years ago

8 0

Answer: pretty sure it is linear

Step-by-step explanation:

STatiana [176]3 years ago

3 0

Linear is the answer

For quadratic either the x or y would need to be raised to the 2nd power which they aren’t

Same for exponential ( no variables are raised to any exponent)

The are no brackets representing taking the absolute value of any variable so that can’t be right

You can always test a few values for x to graph the y result to see that in this case it does graph a line

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I need explanations or answers!!

Reptile [31]

1. 2/7
2. 2/15
3. 5/24
4. 2/11

4 0

3 years ago

Read 2 more answers

Jaron paid $13.80 for 5 tickets to the game. At the same rate, how much would 3 tickets cost? *

jok3333 [9.3K]

Answer:

it will cost 8.28

Step-by-step explanation:

7 0

3 years ago

MARKIN BRAINIEST!!! GIVIN 30PTS!!!

Sedbober [7]

Answer:

(-16x² +10x -3) +(4x² -29x -2)
(2x² -11x -9) -(14x² +8x -4)
2(x -1) -3(4x² +7x +1)

Step-by-step explanation:

I find it takes less work if I can eliminate obviously wrong answers. Toward that end, we can consider the constant terms only:

-3 +(-2) = -5 . . . . possible equivalent
-10 -5 = -15 . . . . NOT equivalent
3(-5) -2(5) = -25 . . . . NOT equivalent
-9 -(-4) = -5 . . . . possible equivalent
-7 -(-5) = -2 . . . . NOT equivalent
2(-1) -3(1) = -5 . . possible equivalent

Now, we can go back and check the other terms in the candidate expressions we have identified.

1. (-16x² +10x -3) +(4x² -29x -2) = (-16+4)x² +(10-29)x -5 = -12x² -19x -5 . . . OK

4. (2x² -11x -9) -(14x² +8x -4) = (2-14)x² +(-11-8)x -5 = -12x² -19x -5 . . . OK

6. 2(x -1) -3(4x² +7x +1) = -12x² +(2 -3·7)x -5 = -12x² -19x -5 . . . OK

All three of the "possible equivalent" expressions we identified on the first pass are fully equivalent to the target expression. These are your answer choices.

7 0

3 years ago

Read 2 more answers

What is 1209➗197 and how do it do it lol

Montano1993 [528]

1209/197 is 6.13

I used a calculator lol

8 0

2 years ago

The head librarian at the Library of Congress has asked her assistant for an interval estimate of the mean number of books check

Verdich [7]

Answer:

$n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11$

So the answer for this case would be n=11 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma =150$ represent the population standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The confidence interval for this case is given by: (740, 920)

We can find the estimate for the mean and we got:

$\bar X = \frac{740+920}{2} = 830$

and the margin of error is given by :

$ME = \frac{920-740}{2}= 90$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =90 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11$

So the answer for this case would be n=11 rounded up to the nearest integer

5 0

3 years ago