Provate school in 2005
f(t)=85+18t
public school
g(t)=95+15t
graph
easy
replace g(t) and f(t) with y
y=18t+85
y=15t+95
input values for t and get values for y
y=18t+85
when t=0 y=85
when t=1 y=103
plot the oints (0,85) and (1,103)
y=15t+95
if t=0 then y=95
if t=1 then y=110
plot the points (0,95) and (1,110)
the easier way would just to be to solve the equatons but anyway
interscection point is (3 and 1/3,145)
so after 3 years (2008) it is about 145
Answer:
{a | always(true)}
Step-by-step explanation:
this means that this will always be true regardless of the value for a
Answer:
Hi there!
The answer to this question is: 6x+3
Step-by-step explanation:
Step 1: combine alike terms
in the equation there are two numbers that end with x: 8x and -2x
you simply add them together to get 6x
Step 2: combine numbers
in this equations there are two numbers: 7 and -4
you simply add them together to get 3
Then your final answer should be 6x+3
Answer:
37 beads
Step-by-step explanation:
Given that:
Adel : Claire = 7 : 4
Let Adel be = A; &
Let Claire be = C
A: C = 7 : 4
7C = 4A
--- (1)
When Adel gave 68 beads to claire, we have:
C + 68 = 25:41
25(C + 68) = 41A
C + 68 = 
--- (2)
Equating (1) and (2) together;
- 187 A = 175 × (-68)
-187 A = - 11900
A = - 11900/ -187
A ≅ 64
From;
C = 36.57
C ≅ 37 beads
