The ball travels 18.3 m at a speed of 35.6 m/s.
How long does the trip take ?
time = (distance)/(speed) = (18.3 m) / (35.6 m/s) = 0.514 second
All during the trip, the ball is spinning at the rate of 29 rev/second.
Spinning at 29 rev/s for 0.514 sec, it completes 14.91 revolutions,
before stopping with a THUNK in the pocket of the catcher's mitt.
The top of the trajectory is the point where it changes from rising to falling. At that exact instant, its vertical speed is zero.
The relationship if time according to the speed of light can be represented using Lorentz' time-dilation equation:
T = To / sqrt( 1 - (v^2/c^2) )
Where:
T = new time = ?
To = original time = 1 minute
v = velocity = 0.6c
c = speed of light
Substituting the given values:
T = 1 / sqrt( 1 - (0.6c^2/c^2) <span>)</span>
T = 1 / sqrt( 1 - (0.6^2) <span>)
</span>T = 1.25
Therefore, the alarm clock would ring for 1.25 minutes.
Answer:
14cm
Explanation:
Mass per gram of the piece of wire;
2g of the wire is found in 1m
Since
100cm = 1m;
So;
100cm of the wire contains 2g of the wire
To provide 0.28g
Since;
2g of wire is made up of 100cm
0.28g of wire will be contained in 
= 14cm
14cm of the wire will contain 0.28g
